Is Kinetic Energy Always Conserved in Collisions?

AI Thread Summary
Kinetic energy is conserved in elastic collisions, where no energy is lost, while inelastic collisions convert some kinetic energy into other forms of energy. Most macroscopic collisions result in energy loss, making perfectly elastic collisions rare. Momentum is conserved in inelastic collisions, but tracking kinetic energy is complicated due to energy transformation. Ideal gas collisions and sub-atomic particle interactions can approximate elastic behavior. The principle of conservation of kinetic energy can be illustrated through calculations of final velocities in two-body collisions.
kreb11
Messages
4
Reaction score
0

Homework Statement


I am asked to explain the conservation of kinetic energy

I am having trouble finding this..I do know that kinetic eneergy is conserved in an elastic collision and part of the KE is changed to some other form of energy in an inelastic collision
 
Physics news on Phys.org
A perfectly elastic collision is defined as one in which there is no loss of kinetic energy in the collision. An inelastic collision is one in which part of the kinetic energy is changed to some other form of energy in the collision. Any macroscopic collision between objects will convert some of the kinetic energy into internal energy and other forms of energy, so no large scale impacts are perfectly elastic. Momentum is conserved in inelastic collisions, but one cannot track the kinetic energy through the collision since some of it is converted to other forms of energy. Collisions in ideal gases approach perfectly elastic collisions, as do scattering interactions of sub-atomic particles which are deflected by the electromagnetic force. Some large-scale interactions like the slingshot type gravitational interactions between satellites and planets are perfectly elastic.

Collisions between hard spheres may be nearly elastic, so it is useful to calculate the limiting case of an elastic collision. The assumption of conservation of momentum as well as the conservation of kinetic energy makes possible the calculation of the final velocities in two-body collisions.

We are now going to see an example of how to use this “principle” which i am going to call the “principle of conservation of kinetic energy”.

Fig 1 below shows two objects traveling towards each other and fig 2 shows the two objects separating after the two objects have separated.

So if the principle of conservation of kinetic energy applies then it means that Sum of kinetic energy before collision = sum of kinetic energy after collision

http://lh3.ggpht.com/_MLcxcpYx4ws/S4iqI2bfwVI/AAAAAAAAAbI/zY5-598E6dQ/s1600-h/clip_image001%5B5%5D.gif

Fig 1 Before collision

Before the collision

Sum of kinetic energy before collision = kinetic energy of object 1 + kinetic energy of object 2

= 1/2m1u12 + 1/2m2v12

http://lh3.ggpht.com/_MLcxcpYx4ws/S4iydzx3GVI/AAAAAAAAAbQ/YgNllKXs98c/s1600-h/clip_image001%5B6%5D%5B4%5D.gif

Fig 2 After collision


After the collision
Sum of kinetic energy after collision = kinetic energy of object 1 + kinetic energy of object 2

= 1/2m1u22 + 1/2m2v22

If you refer back to the principle then

Sum of kinetic energy before collision = sum of kinetic energy after collision

1/2m1u12 + 1/2m2v12 = 1/2m1u22 + 1/2m2v22
 
Last edited:
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top