Niles
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Hi
Say I have two expressions of the form
<br /> F(r, t) = \int{dr'\,dt'\,\,x(r,r',t,t')g(r',t')}<br />
and
<br /> F'(r, t) = \int{dt'\,\,x'(r,t,t')g'(r, t')}<br />
It is clear that F' is local in space, whereas F is non-local in space. Is it correct of me to say that F' describes an isotropic object? I.e., does isotropic = translational invariance?
Niles.
Say I have two expressions of the form
<br /> F(r, t) = \int{dr'\,dt'\,\,x(r,r',t,t')g(r',t')}<br />
and
<br /> F'(r, t) = \int{dt'\,\,x'(r,t,t')g'(r, t')}<br />
It is clear that F' is local in space, whereas F is non-local in space. Is it correct of me to say that F' describes an isotropic object? I.e., does isotropic = translational invariance?
Niles.