Is Mandatory LaTeX Implementation on PF Beneficial for Members?

  • Context: LaTeX 
  • Thread starter Thread starter Greg Bernhardt
  • Start date Start date
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Discussion Overview

The discussion revolves around the implementation of LaTeX on Physics Forums (PF) and its potential benefits for community members. Participants explore the functionality, usability, and challenges associated with using LaTeX for mathematical expressions and equations within forum posts.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants express excitement about the new LaTeX feature, highlighting its potential to enhance the forum's capabilities.
  • There are discussions about the ease of use of the new LaTeX code, with some members sharing their attempts and experiences.
  • Several participants report issues with the display of LaTeX images, noting that they may not show up in previews or topic reviews.
  • Concerns are raised about the server's performance and the generation of LaTeX images, with some participants experiencing delays and unexpected substitutions of images.
  • Some members question the reliability of the LaTeX implementation, citing instances where the displayed output does not match the input code.
  • Participants share tips and corrections for using LaTeX effectively, including specific commands and syntax adjustments.
  • There is a mention of caveats regarding the current limitations of the LaTeX feature, including issues with image generation and potential platform dependencies.

Areas of Agreement / Disagreement

Participants generally agree on the excitement surrounding the LaTeX implementation, but multiple competing views remain regarding its reliability and usability. The discussion includes both positive feedback and concerns about technical issues, indicating that the topic is still unresolved.

Contextual Notes

Limitations include unresolved issues with image generation, potential platform-dependent behavior, and discrepancies between input code and displayed output. These factors contribute to ongoing uncertainty about the effectiveness of the LaTeX feature.

  • #31
Originally posted by enigma
Should we be worried if it gives the "Latex image is being generated, please reload" message?
Perhaps... I'm not sure what's hanging it up. I'm trying to figure that out now... eek.

- Warren
 
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  • #32
<br /> \frac{1}{2}<br />
 
  • #33
Argh... all of a sudden the server seems to be having a problem...

- Warren
 
  • #34
<br /> \frac{3}{4}<br />
 
  • #35
I just looked through the lists.

Are there commands for double and triple integral as well as surface and volume integral symbols?
 
  • #36
looks like we bogged the server down, once it's fixed we'll open up testing again.
 
  • #37
Woohoo... sorry about the mistake guys.

\gamma \equiv \frac{1}{\sqrt{1 - v^2/c^2}}

- Warren
 
Last edited:
  • #38
Do your worst, fellas... let's see if I forgot to do anything else.

- Warren
 
  • #39
\alpha

\beta

\gamma
 
  • #40
I tried this one as an edit to a previous post, and it did not work there upon reloading.

<br /> \psi<br />
 
  • #41
A psi doesn't work?

\psi
 
  • #42
What I typed up there was "\psi"; instead, I see what I would have expected afger typing "\alpha".

I guess I'll just have to wait a little longer.
 
  • #43
okay, let's try
<br /> $\Delta V_{(R_{1}\rightarrow R_{2})}= V_{R_{1}}\left[\sqrt{\frac{2R_{2}}{R_{1}+R_{2}}}-1 \right]$
 
Last edited:
  • #44
Originally posted by chroot
A psi doesn't work?

\psi

Apparently.
 
  • #45
Originally posted by ahrkron
What I typed up there was "\psi"; instead, I see what I would have expected afger typing "\alpha".

I guess I'll just have to wait a little longer.
Yeah something is weird...

this

<br /> \psi<br />

is different from this

\psi

and it shouldn't be.

- Warren
 
  • #46
There we go!

B_0 \rightarrow J\psi K^0_s
 
  • #47
The server is trying to confuse us all! :smile:

Now you see it, now you don't, now you complain, now it's ok, it looked different just a minute ago...
 
  • #48
Originally posted by ahrkron
The server is trying to confuse us all! :smile:

Now you see it, now you don't, now you complain, now it's ok, it looked different just a minute ago...

The reason is looks wacky is simple:

1) Some graphics take longer than others to create; they're all in background processes. Sometimes, you view the thread at first, but your graphics are not done yet.

2) When a graphic is not present (because it is not done being generated), the stupid webserver will try to help you out by sending you another graphic with a similar filename. It's supposed to help you avoid 404 errors for spelling mistakes. I really hate this "feature," because in this case, it results in your post showing someone else's graphics temporarily until yours are done!

I'm going to fix this in a few minutes.. hold on.

- Warren
 
  • #49
Okay, let's try this. This should fix the weirdness.

<br /> \Delta V = - I_{sp} \times g_0 \times \ln{\frac{M_L + M_i}{M_L + M_i + M_P}}<br />

- Warren
 
Last edited:
  • #50
This stuff looks GREAT! Let's have a go at it

\int_{-\infty}^{\infty}


\stackrel \cdot x

\ddot{x} = -g
\int \ddot{x}dt = \int -gdt
\dot{x} = -gt + C
\dot{x}(0)= V_0 \Rightarrow C = V_0
\int \dot{x}dt = \int -gt + V_0 dt
x(t)= - \frac {gt^2} {2} + V_0t + X_0


\mbox{ x=y} \mbox{\iff |x-y| &lt; \epsilon} \forall \mbox{ \epsilon \in \Re}

\ddot{x} = \frac {d^2x} {dt^2}
 
Last edited:
  • #51
<br /> \begin{pmatrix} D_1t&amp;-a_{12}t_2&amp;\dots&amp;-a_{1n}t_n\\<br /> -a_{21}t_1&amp;D_2t&amp;\dots&amp;-a_{2n}t_n\\<br /> -a_{n1}t_1&amp;-a_{n2}t_2&amp;\dots&amp;D_nt<br /> \end{pmatrix}<br />
 
Last edited:
  • #52
\frac{a}{b}
 
  • #53
<br /> \int\!\!\!\int\!\!\!\int f(u,v,w)\,du\,dv\,dw<br />
 
Last edited:
  • #54
\mu
\nu
\xi
\phi
 
  • #55
g_{\mu\nu}

g_{\mu\nu}

g_{\mu\nu}

g_{\mu\nu}

g_{\mu\nu}

g_{\mu\nu}

g_{\mu\nu}

g_{\mu\nu}
 
  • #56
<br /> \int_{0}^{1} x dx = \left[ \frac{1}{2}x^2 \right]_{0}^{1} = \frac{1}{2}<br />

v(t) = v_0 + \frac{1}{2} a t^2

<br /> \int_{0}^{1} y dy = \left[ \frac{1}{2}y^2 \right]_{0}^{1} = \frac{1}{2}<br />

v(t) = v_0 + \frac{1}{2} a t^2

<br /> \int_{0}^{1} z dz = \left[ \frac{1}{2}z^2 \right]_{0}^{1} = \frac{1}{2}<br />

v(t) = v_0 + \frac{1}{2} a t^2
 
  • #57
Test.
 
  • #58
Originally posted by chroot
<br /> \int_{0}^{1} x dx = \left[ \frac{1}{2}x^2 \right]_{0}^{1} = \frac{1}{2}<br />

v(t) = v_0 + \frac{1}{2} a t^2

<br /> \int_{0}^{1} y dy = \left[ \frac{1}{2}y^2 \right]_{0}^{1} = \frac{1}{2}<br />

v(t) = v_0 + \frac{1}{2} a t^2

<br /> \int_{0}^{1} z dz = \left[ \frac{1}{2}z^2 \right]_{0}^{1} = \frac{1}{2}<br />

v(t) = v_0 + \frac{1}{2} a t^2
 
  • #59
Originally posted by chroot
<br /> \int_{0}^{1} u du = \left[ \frac{1}{2}u^2 \right]_{0}^{1} = \frac{1}{2}<br />

v(t) = v_0 + \frac{1}{2} a t^2

<br /> \int_{0}^{1} v dv = \left[ \frac{1}{2}v^2 \right]_{0}^{1} = \frac{1}{2}<br />

v(t) = v_0 + \frac{1}{2} a t^2

<br /> \int_{0}^{1} w dw = \left[ \frac{1}{2}w^2 \right]_{0}^{1} = \frac{1}{2}<br />

v(t) = v_0 + \frac{1}{2} a t^2
 
Last edited:
  • #60
Originally posted by chroot
g_{\mu\nu}

g_{\mu\nu}

g_{\mu\nu}

g_{\mu\nu}

g_{\mu\nu}

g_{\mu\nu}

g_{\mu\nu}

g_{\mu\nu}
 

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