Is Mid(n) an Underestimate for Trapezoid Integration on an Increasing Function?

AI Thread Summary
TRAP(n) represents the trapezoidal approximation of the integral F(x) dx from a to b using n trapezoids. It is established that TRAP(n) equals the average of Left(n) and Right(n), where Left(n) uses the left endpoint for rectangle heights. The discussion highlights that for a function f that is increasing and has a positive second derivative (f'' > 0), the midpoint approximation Mid(n) underestimates the integral. This is due to the curvature of the function, which causes the midpoints to fall below the actual function values. The conclusion emphasizes the relationship between the function's properties and the accuracy of the Mid(n) approximation.
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For F(x) dx from a to b show TRAP(n)=Left(n) + 1/2 (f(b)-f(a))*delta x
 
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I assume that TRAP(n) is the value you would get using n trapezoids to approximate the area. Is Left(n) the approximation using rectangles with height the left endpoint?

If so, you might note that TRAP(n)= (Left(n)+ Right(n))/2 and that the sums involved in Left(n) and Right(n) differ only at the two endpoints.
 
Thanks for the help but now i have another problem
Let f''> 0 and suppose f is increasing on [a,b], show that Mid(n) is an underestimate for f(x) dx from a to b.
 
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