Is My Clock Cycle Calculation Accurate for a 2.5 GHz CPU?

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SUMMARY

The discussion centers on calculating the clock cycle for a CPU operating at 2.5 GHz. The correct formula to determine the clock cycle in nanoseconds is established as 10^-9 seconds multiplied by the frequency in hertz, resulting in a period of 2.5 nanoseconds for a 2.5 GHz CPU. Participants emphasize the inverse relationship between frequency and period, clarifying that a higher frequency corresponds to a shorter period. The calculation is confirmed as accurate, with a reminder to include the division operation in future calculations.

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  • Understanding of CPU frequency and clock cycles
  • Basic knowledge of nanoseconds and their conversion
  • Familiarity with mathematical operations involving exponents
  • Concept of inverse relationships in physics
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Computer engineers, hardware designers, and students studying computer architecture will benefit from this discussion, particularly those interested in CPU performance calculations.

DanjoJojo
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TL;DR
What is the duration of a clock cycle (in nanoseconds) for a CPU running at 2.5 GHz?
So far I have come to the understanding that a nanosecond is one billionth of a second or 10-9 seconds. So I found this formula to calculate the clock cycle in nanoseconds, for a CPU running at 2.5 GHz.

10^-9 x 2.5 x 10^9 = 2.5 nanoseconds

Am I missing any important steps with my calculation? Is this accurate?
 
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A 1GHz frequency would be 1ns period. A higher frequency would involve a smaller period. What formula are you using?
 
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Also, is this for schoolwork?
 
Period is inversely proportional to frequency. I don't see the 'devide' operation in your calculation.
 

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