Is My pH Calculation for NaOH Correct?

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The pH calculation for a 1x10^-2 NaOH solution is confirmed as correct, resulting in a pH of 12 when using the formula pH + pOH = 14 at room temperature. The discussion emphasizes that this formula is valid at 25°C, though accuracy may vary at different temperatures. A user then inquires about calculating the pH of a 1x10^-5 HNO3 solution, seeking clarification on whether the same method applies to strong acids. It is affirmed that HNO3 is a strong acid and is fully dissociated, making a pH of 5 plausible. The conversation highlights the importance of understanding the dissociation of strong acids and bases in pH calculations.
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i need to Calculate the pH of 1x10^-2 NaOH

so i did like this: [OH-]=10^-2

POH=-log[OH-]=-log[10^-2]=2

and if i work with the Formula :pH+POH=14 so i will get pH+2=14

so the for the 1x10^-2 NaOH the ph=12 do i correct?

thnaks.
 
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Yes, assuming its temperature is around room temperature.
 
Water ion product.

pH + pOH = 14 works perfectly well for 25 deg. Depending on the required accuracy it may be acceptable or may be not acceptable for other temperatures.
 
thanks to both of you about your answer.

and yes i speak about 25c.

i need help to Calculate the pH of 1x10^-5 of HNO3

to Calculate base as i showed here is the same way to Calculate acid like is ask now?

thanks.
 
is it possible that the ph of HNO3 is 5 ?
 
Yes, you can assume HNO3 is a strong acid, 100% dissociated.
 
yes it is possible...
 
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