Is p(r) = (2/R²)r the Only Solution to the Integral Uniqueness Problem?

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Let p be a continuous function such that for all r1, r2 in [0,R], ∫r2r1p(r)dr=(r22-r12)/R2.

I'm trying to prove that p(r)=(2/R2)r.

Question: Must p be unique? I'm not sure how to prove/disprove this.
 
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Try showing that p(r) - 2r/R^2 must be zero. Hint: Prove that if it isn't zero, there is a nondegenerate interval [r_1, r_2] on which it is either strictly positive or strictly negative, and derive a contradiction.
 
HyperbolicMan said:
Let p be a continuous function such that for all r1, r2 in [0,R], ∫r2r1p(r)dr=(r22-r12)/R2.

I'm trying to prove that p(r)=(2/R2)r.

Question: Must p be unique? I'm not sure how to prove/disprove this.

Let r1 be constant and r2 variable. Take the derivative of the integral [(r22-r12)/R2]
with respect to r2 and rename r2 to be r.

The derivative is unique.
 
Thanks for the help!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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