The problem is that when I asked you what the action was, you could not give it to me. You stated that the electron and photon have the same "action potential" yet you can not give me what that potential is when I asked. You need to start learning more about these things before you start basing conclusions upon them.
More importantly, how would having the same action dictate that two situations are the same? Going from the definition you reference, energy times time, I could give you the "action" in this sense of a 1 ton car that travels 1 second at 100 km/hr and say that it is the same as the action of a mole of C_60 buckyball traveling at 54 ft/s for 1 hour. What is of interest is how the action relates to physics in general, through its use in Lagrangian physics. If you learned about Lagrangian mechanics then you would easily see the answer to your question.
As for Planck's constant, to me, it really doesn't mean anything of much consequence. It's just a constant, we can always set it to any arbitrary non-zero number depending on our desired system of units. For example, if we were to use natrural units, then c=\hbar=1. The ubiquitious nature of \hbar popping up everywhere makes it rather difficult to describe what it is since it is present in the basic principles of quantum mechanics, like Schroedinger's equation or Feynman's path integral formulation. However, it is of interest that classical mechanics can be recovered by taking the limit of \hbar to zero with the path integral formulation.