Is <S> equal to the intersection of all ideals in R that contain S?

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SUMMARY

The discussion centers on the equivalence of the ideal generated by a subset S of a commutative ring R with unity and the intersection of all ideals in R that contain S. Specifically, it establishes that is equal to both the intersection of ideals containing S and the sum of products of elements from S and R. The key relationships are outlined as = J (intersection of ideals) and = K (sum of products), with a focus on proving the implication J ⊆ K.

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Homework Statement


The following are equivalent for S[tex]\subseteq[/tex]R, S[tex]\neq[/tex][tex]\oslash[/tex], and R is a commutative ring with unity(multiplicative identity):

1. <S> is the ideal generated by S.
2. <S> = [tex]\bigcap[/tex](I Ideal in R, S[tex]\subseteq[/tex]I) = J
3. <S> = {[tex]\sum[/tex]risi: is any integer from 1 to n, ri[tex]\in[/tex]R [tex]\forall[/tex]i and si[tex]\in[/tex]S [tex]\forall[/tex]i} = K

Homework Equations


The Attempt at a Solution


It's been some time since I worked on this and at the time I understood everything I was working on but now when I look at it, I'm thoroughly confused. Where I got stuck is showing 2 [tex]\Rightarrow[/tex] 3. I've got, assume <S> = J. Choose a [tex]\in[/tex]K. Let I be an ideal of R that contains S. Because each ri[tex]\in[/tex]R, si[tex]\in[/tex]S, each risi[tex]\in[/tex]I by IO closure. Then a [tex]\in[/tex] I by closure under addition. Thus a [tex]\in[/tex] J and K[tex]\subseteq[/tex]J.

I'm having trouble with starting to show that J[tex]\subseteq[/tex]K.
 
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[tex]S \subseteq I \Rightarrow \forall s \in S, (s) \subseteq I[/tex]
 
Last edited:

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