Is Sin^2(a) Equal to Sin^2(b) + Sin^2(c) Only in a Right Triangle at A?

AI Thread Summary
The discussion centers on proving that sin^2(a) = sin^2(b) + sin^2(c) if and only if triangle ABC is a right triangle at angle A. Participants express confusion over the proof, noting that the equation holds true specifically when angle A is the right angle. It is emphasized that transforming sin^2(a) can aid in the proof, particularly by applying Pythagorean theorem concepts. The relationship between angles in a triangle is also highlighted, with a+b+c equating to π being a common trait of all triangles. Ultimately, the proof hinges on recognizing that angle A must be the right angle for the equation to hold.
Andrax
Messages
117
Reaction score
0

Homework Statement


prove that sin^2(a)=sin^2(b)+sin^2(c) if and only if ABC is a right triangle in A

i worked really hard on this one I'm really confused why i didn' get the answer

Homework Equations





The Attempt at a Solution


a+b+c=pi
tried turning everythng to cos 2x didn't helpi really couldn't do this one, can't use complex numbers by the way...please help
 
Physics news on Phys.org
Well, a+b+c = \pi is going to be true of all triangles, so that's not necessarily going to be much help.

What does ABC being a right-angled triangle in A imply for the value of a? What does that imply for the value of b+c? What does that imply for the value of \sin^2 a?
 
Snark1994 said:
Well, a+b+c = \pi is going to be true of all triangles, so that's not necessarily going to be much help.

What does ABC being a right-angled triangle in A imply for the value of a? What does that imply for the value of b+c? What does that imply for the value of \sin^2 a?

i tried everything you said also transforming \sin^2 a won't help me since i want to keep sin a
 
Andrax said:
transforming \sin^2 a won't help me since i want to keep sin a

Transforming \sin^2 a will help you. In fact, the easiest way I can see of proving the result from right-to-left (remember for an "if and only if" you need to prove it both ways) is to show that \sin^2 a = k = \sin^2 b + \sin^2 c for some specific number k whose value you'll have to work out.

Like I asked, if the triangle is right-angled in A, what can you say about the value of 'a'? You can be very specific!
 
\sin((\pi/2) - \theta)=\cos(\theta)

Also, for this to be true, a must be the right angle of the right triangle.
 
SammyS said:
\sin((\pi/2) - \theta)=\cos(\theta)

Also, for this to be true, a must be the right angle of the right triangle.

solved using Pythagoras's theorem --> let abc be a triangle wehave sin a^2 = AB^2 etc..
thank everyone..
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

Similar threads

Back
Top