Is the Collision Between Two Moving Carts Elastic?

  • Thread starter Thread starter SteelDirigibl
  • Start date Start date
AI Thread Summary
In the collision between a 20 kg cart and a 10 kg cart, the larger cart traveling at 8 m/s to the right comes to a stop after the collision, while the smaller cart moves to the right at 10 m/s. The calculations show that the momentum before and after the collision is conserved, but the kinetic energy decreases from 820 J to 500 J, indicating that the collision is inelastic. The discussion highlights that energy loss occurs due to sound and heat, which is typical in real-world collisions. The reasoning behind the larger cart stopping is that it transfers its energy to the smaller cart, resulting in a halt for the larger cart. Thus, the collision is confirmed to be inelastic, aligning with the calculations and physical principles.
SteelDirigibl
Messages
40
Reaction score
0

Homework Statement


A 20kg cart traveling to the right at 8 m/s collides head-on with a 10 kg car traveling 6 m/s to the left. After the collision, the 10 kg cart is traveling 10 m/s to the right
a) What is the velocity of the 20 kg cart after the collision?
b) determine whether or not the collision is elastic (show calculations)
c) Discuss whether or not your answers to part a and b are reasonable. Include specific reasons why you think the answers are or are not reasonable


Homework Equations


p=mv

KE=1/2mv^2


The Attempt at a Solution



So pretty simple I think for the first two parts, but I got to thinking.

Well here's the math: 8*20=160 right, 10*6=60 left, so total 100 to right. Then after, the small cart is 10*10 or 100 to the right, so the 20kg cart would be stopped, according to the math.
Is this reasonable? it's larger and going faster?

Moving on... elasticity just means KE is equal before and after. before is 820 and after is 500. Therefore not elastic. This seems to make sense in the real world because energy would be lost by sound, and i want to say friction as heat, even though we didnt factor friction into the motion.

So I have my numbers, pretty sure they are right. is it reasonable? it doesn't seem like a larger cart moving faster would stop, but then I also think back to those metal balls that bounce back and forth and transfer their energy. Does this seem right?
 
Physics news on Phys.org
All your math is right. The carts don't need to behave like those balls because the collisions between them are very nearly elastic, whereas the collision between these two carts is not.
 
if it were elastic, shouldn't i get the same KE for before and after? it's 320 (Joules?) difference.
 
The collision between the carts is NOT elastic. The collision between those steel balls is.
 
ok that's what i thought. so since the larger mass is larger and moving faster, how does it stopping make sense? obviously the math shows it but it just seems like it would have some motion left. I guess that it transfers all it's energy to the smaller box and the rest (the extra 320) is dispersed through sound, etc, other energy loss sources?
 
SteelDirigibl said:
ok that's what i thought. so since the larger mass is larger and moving faster, how does it stopping make sense? obviously the math shows it but it just seems like it would have some motion left. I guess that it transfers all it's energy to the smaller box and the rest (the extra 320) is dispersed through sound, etc, other energy loss sources?

Yes. All the smaller box does is bring the larger box to a halt. The larger box has to stop the smaller one and force it to go in the opposite direction.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top