Is the Defined Complex Scalar Product a Valid Scalar Product?

SoapyIllusion
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Homework Statement



This is what we are given in the assignment:

Recall a definition of scalar product on complex numbers. Let A = [[3,1],[1,2]]. Prove that the product as defined by:

* => dot product

u * v := uT * A * conjugate(v)

( = Sum from i,j=1 to 2; uiAijconjugate(vj) )

is a scalar product on C according to the definition.

Homework Equations



We are give that the following equation will be useful:

2(ac) >= -a2 -c2 for all a,c as elements of R

The Attempt at a Solution



There are many of us working on this and we were not even sure exactly how to start this problem. It is trivial to prove the Sum given is equal to uT * A * conjugate(v). But from there we weren't sure exactly what else to prove.

Any help would be extremely appreciated
 
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Have you written out the computations?
For
u= \begin{bmatrix}u_1 \\ u_2\end{bmatrix}
v= \begin{bmatrix}v_1 \\ v_2\end{bmatrix}<br /> <br /> The product is <br /> u*v= \begin{bmatrix}u_1 & u_2\end{bmatrix}\begin{bmatrix}3 & 1 \\ 1 & 2\end{bmatrix}\begin{bmatrix}\overline{v_1} \\ \overline{v_2}\end{bmatrix}= (3u_1+ u_2)\overline{v_1}+ (u_1+ 3u_2)\overline{v_2}<br /> <br /> Now what are the requirements for a scalar product- what is the definition? Does this satisfy those requirements?
 
HallsofIvy said:
Have you written out the computations?
For
u= \begin{bmatrix}u_1 \\ u_2\end{bmatrix}
v= \begin{bmatrix}v_1 \\ v_2\end{bmatrix}<br /> <br /> The product is <br /> u*v= \begin{bmatrix}u_1 & u_2\end{bmatrix}\begin{bmatrix}3 & 1 \\ 1 & 2\end{bmatrix}\begin{bmatrix}\overline{v_1} \\ \overline{v_2}\end{bmatrix}= (3u_1+ u_2)\overline{v_1}+ (u_1+ 3u_2)\overline{v_2}<br /> <br /> Now what are the requirements for a scalar product- what is the definition? Does this satisfy those requirements?
<br /> <br /> Yes I got this far, my only problem is that I don't see any logical next step, I may be missing something very obvious, but even after reading more about the definition of scalar product I don't understand what more there is to prove<br /> <br /> And I also do not understand the purpose of the matrix A
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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