Aug 8, 2011 #1 dimension10 Messages 371 Reaction score 0 According to Wolfram|Alpha, sometimes, the derivative of arctangent is \frac{d}{dx}\arctan x =\frac{1}{1+{x}^{2}} and sometimes, \frac{d}{dx}\arctan x =\frac{\arctan x}{x} So are both of them equal? Attachments EWE.pdf EWE.pdf 474.7 KB · Views: 450
According to Wolfram|Alpha, sometimes, the derivative of arctangent is \frac{d}{dx}\arctan x =\frac{1}{1+{x}^{2}} and sometimes, \frac{d}{dx}\arctan x =\frac{\arctan x}{x} So are both of them equal?
Aug 8, 2011 #2 asmani Messages 104 Reaction score 0 The second case is actually \frac{d}{d\times x}\arctan (x)=\frac{\arctan (x)}{x}.
Aug 8, 2011 #3 HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 984 Okay, you have lost me. What does \frac{d}{d\times x} mean?
Aug 8, 2011 #4 asmani Messages 104 Reaction score 0 d over d multiplied by x, where d is a constant. Wolframalpha simplifies this to 1/x.
Aug 9, 2011 #5 dimension10 Messages 371 Reaction score 0 Oh. So that must have happened the other time too...
Aug 9, 2011 #6 asmani Messages 104 Reaction score 0 Compare: Notice the blank between d and x in the left one. What input did you give in each time? Attachments Untitled.jpg 2.9 KB · Views: 484
Aug 9, 2011 #7 HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 984 asmani said: d over d multiplied by x, where d is a constant. Wolframalpha simplifies this to 1/x. Thanks.
asmani said: d over d multiplied by x, where d is a constant. Wolframalpha simplifies this to 1/x. Thanks.