I Is the Dot Product of Unit Vectors Related to Magnitudes and Angle Between Them?

AI Thread Summary
The discussion focuses on the relationship between the dot product of unit vectors and the magnitudes and angles between them. It highlights that when dotting unit vectors, the result can be expressed in terms of sine and cosine functions related to spherical coordinates. The participants clarify that the dot product of unit vectors indeed reflects the cosine of the angle between them, despite the initial confusion regarding the sine and cosine terms. The conversation concludes with a successful understanding of how to express the cosine of the angle in terms of the spherical coordinates. Overall, the thread emphasizes the connection between vector representation in different coordinate systems and the geometric interpretation of the dot product.
Abdulwahab Hajar
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Okay so I understand that in order to represent a vector which is in cartesian coordinates in spherical coordinates.. we use the transformation which is obtained by dotting the unit vectors.
So my question goes like this:
when we dot for example the unit vector ar^ with x^ we obtain sin(theta) * cos(phi), however can't the dot product be interpreted as the magnitudes multiplied by the cos of the angle between them.
In this case the magnitudes are 1 because they are unit vectors but how can sin(theta) * cos(phi) equal cos(angle between ar^ and x^)
I know my notation sucks please pardon me it's my first time posting... I have no notation at all :(

Thank you for the help
 
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If you identify the angle between ##\vec r = r\hat r## and ##\vec x = x\hat\imath## (you OK with i-j-k unit vectors?) for an arbitrary ##\vec r## as ##\alpha## to distinguish it from the ##\theta## and ##\phi## of the spherical polar coordinates... then ##\hat r\cdot \hat\imath = \cos\alpha## right?

You can express ##\cos\alpha## in terms of ##\theta## and ##\phi##.
Give it a go. ie. try first for ##\theta=\pi/2## and ##\phi >0##, then for ##\phi=0## and ##0<\theta<\pi/2## ... then combine the results.
 
Awesome haha I actually got it :)
thanks a million sir
 
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