Is the Electric Field Always Conservative or Can it be Non-Conservative?

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The discussion clarifies that the electric field is generally considered conservative, leading to the integral of the electric field around a closed loop being zero in electrostatics. However, in cases involving changing magnetic fields, the integral is equal to the negative rate of change of magnetic flux, indicating non-conservative behavior. This distinction is often misrepresented in textbooks, particularly in relation to Kirchhoff's Voltage Law. It's important for students to recognize when the special case of a conservative electric field applies, especially in AC circuits with inductors. Understanding these nuances is crucial for accurate application in physics and circuit analysis.
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In some books I have seen:

\oint \mathbf{E} \cdot d\mathbf{s}=0

Since the Electric Field is meant to be conservative.


Elsewhere, however, I have also seen:

\oint \mathbf{E} \cdot d\mathbf{s} = -\frac{d\Phi_B}{dt}


What's going on here?

Thanks
 
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The first case is for electro-statics (no changing fields) and hence is true for the special case when \frac{d\Phi_B}{dt}=0
 
Ah, thanks Matterwave
 
Matterwave said:
The first case is for electro-statics (no changing fields) and hence is true for the special case when \frac{d\Phi_B}{dt}=0

This is true, of course.

What is amazing is that circuit or physics textbooks often quote the special case erroneously. They sometimes even call it a version of Kirchoff's Voltage Law, which is not correct. Any AC circuit that includes an inductor violates the quoted special case. Students should keep an eye out for this, and make sure the special case is really valid.
 
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