Is the Escape Velocity of a 10,500kg Spaceship from Earth Calculated Correctly?

AI Thread Summary
The escape velocity for a 10,500kg spaceship from Earth is calculated using the formula 2GM/R. The user initially calculated the escape velocity to be 3.464*10m/s but received feedback that the equation was incomplete and lacked clarity. Participants in the discussion emphasized the need for a complete equation and accurate substitution of values. The conversation highlights the importance of precision in calculations related to physics. Properly addressing these details is crucial for determining the correct escape velocity.
kubombelar
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Homework Statement

calculate the escape velocity of a 10,500kg spaceship from earth. mass of Earth is 5.98*10kg and radius of the Earth is 6.38*10kg.

elevant equations
2GM/R

The Attempt at a Solution

Using the formula i found escape velocity to be 3.464*10m/s. Is this correct?
 
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If it was correct, you would have to be careful driving your car up hills - you could easily go fast enough to escape from the Earth!
That equation has no equal sign so it isn't clear what it is. Can you write it completely and then show the numbers you substituted in? Probably just a small error or two.
 
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