Is the Function f(x) = x^5 - x^3 + 2x Invertible?

alexs2jennisha
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Homework Statement



1. Show that the function f(x) = x5 -x3 +2x is invertible. Compute the derivative of f-1
at 2.


The Attempt at a Solution


To find f-1 I switched x and y which gave me x = y5 - y3 + 2y

this is where i got stuck because I am not sure how to solve for y after that step.

Can the y5 - y3 become y2?

Thanks
 
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alexs2jennisha said:

Homework Statement



1. Show that the function f(x) = x5 -x3 +2x is invertible. Compute the derivative of f-1
at 2.


The Attempt at a Solution


To find f-1 I switched x and y which gave me x = y5 - y3 + 2y

this is where i got stuck because I am not sure how to solve for y after that step.
Lucky for you, you weren't asked to calculate ##f^{-1}##, just show it exists. Can you show, for example, that ##f## is increasing?
Can the y5 - y3 become y2?

Of course not.
 
alexs2jennisha said:
Can the y5 - y3 become y2?

one really good way to see if numeric algebra works is to take a simple case and see what happens. what if y=1?? then you know the answer to be zero yet if you adopt your proposition we see the answer is 1, which is of course incorrect.

hope this helps for the future
 
What is necessary for a function to be invertible ?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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