Is the Kernel of a 9x10 Matrix with Rank 5 Four-Dimensional?

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SUMMARY

The discussion confirms that if the rank of a 9x10 matrix A is 5, then the kernel of A is indeed 4-dimensional. This conclusion is derived from the dimension theorem, which states that the sum of the rank and nullity of a linear transformation must equal the dimension of the domain. In this case, the domain is R^10, leading to a nullity of 5, as the total dimension is 10. The participants clarify that analyzing the rank and nullity of the transformation T and its matrix representation A yields the same results.

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Homework Statement


1. True or False: If the rank of a 9x10 matrix A is 5, then the kernel of A is 4-dimensional

Homework Equations


The Attempt at a Solution


1. I was explained that it is true because the rank and nullity of A must be 10, but I don't understand why. I understand the dimension theorem that states the sum of the nullity and rank of a transformation must equal the dimension of the domain but how is the matrix represented as a linear transformation. and what would be the domain of this transformation. I was thinking if its a 9x10 matrix T: R^10 to R^9 could a transformation and the matrix representation of T could be A. Then R^10 would be the domain and so the dimension is 10. That is why the nullity must be 5 and not 4. If I am wrong or if there is another way of approaching this problem give me your input.

Also the way i solved the problem i calculated the nullity and rank of T rather then the matrix representation of T which is = A. Is doing it as I did the same, because I feel like I am looking not at the rank and nullity of A.
 
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I think what you did was right, no need to worry about the difference between A and T, they are essentially identical
 
Last edited:

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