Is the Key Correct? Simplifying Complex Numbers Using Roots of Unity

[zcserei]

Homework Statement

I've been recapitulating some lessons we learned in high school 2 years ago for the exams I need to take this year. There was this exercise I couldn't solve in a nice way.

z^2005+(1/z^2005) if we know that z^2+z+1=0

Homework Equations

I couldn't came up with a good solution, so I looked at the key at the end of the book, and it said that from z^2+z+1=0 => z^3=1, and then you do z^2005=(z^3)^668+z=1^668+z=1+z

The Attempt at a Solution

I calculated the root for the equation, and I found that it is (-1±i√3)/2. Now, that complex number definitely isn't 1 on the third power, and I can't take (1+z)+1/(1+z) too far either.
Where did I mess up? Is the key in my book correct?

Thank you for your answers.

 

[hunt_mat]

Okay, they get z^{3} from:
<br /> z^{2}+z+1=0\Rightarrow z^{3}+z^{2}+z=0\Rightarrow z^{3}-1=0\Rightarrow z^{3}=1<br />
Then
<br /> z^{2004}=(z^{3})^{668}=1^{668}=1<br />
From here it is clear what to do.

 

[statdad]

"Now, that complex number definitely isn't 1 on the third power"

Are you sure about that? Check it again.

As a different approach: remember that

<br /> A^3 -1 = (A-1)(A^2 + A + 1)<br />

so, given z^2 + z + 1 = 0

<br /> \begin{align*}<br /> z^2 + z + 1 &amp; = 0 \\<br /> \frac{z^3 - 1}{z-1} &amp; = 0 \\<br /> z^3 - 1 &amp; = 0 \\<br /> z^3 &amp; = 1<br /> \end{align*}<br />

I can eliminate the denominator since it is obvious that z is not equal to 1. This gets you to the same statement about z as direct calculation, but without having to work with complex numbers (not that that is a huge problem). Once here, the rest of the solution goes as you note.