You can use 86,400 seconds as the length of the day, that times 28 days, the time it takes for one revolution of the moon around the Earth, is about 2,400,000 seconds. Using the distance to the moon as 225,000 miles (it varies but for this exercise, that's close enough), which is the radius of the more or less circular path the moon takes around the Earth, it's not circular but elliptical but let's call it circular for this discussion. So times 2 is the diameter, 450,000 miles, times pi makes that circle 1.4 million miles give or take. So divide 1,400,000 miles by 2,400,000 seconds and you find the moon traveling in its Earthy orbit going about 0.6 miles per second. Multiply that by 3600 and you get miles per hour, which is a bit over 2000 miles per hour. At the equator the Earth is spinning about 1000 miles per hour (it's about 25,000 miles around and it takes 24 hours so divide the two and you get close to 1000 miles per hour) So the moon is going in it's orbit twice as fast as the Earth spins on it's axis. Since the rate of the moon's spin is the same as it's orbital period of about 28 days, you always see only one side of the moon. (not completely correct since it does wobble a bit and you can see just a bit around the 'corner' of the moon)