Abigale
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Hey Guys,
I regard two operators \Psi , \Phi, that don't commute.
Does the product-rule, looks like that?
$$\nabla (\Phi \Psi)
= \Psi (\nabla \Phi)
+\Phi (\nabla \Psi)
$$
THX
I regard two operators \Psi , \Phi, that don't commute.
Does the product-rule, looks like that?
$$\nabla (\Phi \Psi)
= \Psi (\nabla \Phi)
+\Phi (\nabla \Psi)
$$
THX