Is the Sequence an+2=an+1+an Monotonically Increasing?

analysis001
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Homework Statement


Prove that an+2=an+1+an where a1=1 and a2=1 is monotonically increasing.


Homework Equations


A sequence is monotonically increasing if an+1≥an for all n\inN.


The Attempt at a Solution


Base cases:
a1≤a2 because 1=1.
a2≤a3 because 1<2.

Am I supposed to prove that an≤an+1 now? I'm not sure how to do that.
 
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analysis001 said:

Homework Statement


Prove that an+2=an+1+an where a1=1 and a2=2 is monotonically increasing.


Homework Equations


A sequence is monotonically increasing if an+1≥an for all n\inN.

The Attempt at a Solution


Base cases:
a1≤a2 because 1=1.
a2≤a3 because 1<2.

Am I supposed to prove that an≤an+1 now? I'm not sure how to do that.
a2 ≥ a1 because 2 ≥ 1 . After all, a2 = 2 and a1 = 1 .

Now, what you need to do:
Assume that the statement is true for some k, where k ≥ 1 .
I.e.:
Assume that ak+1 ≥ ak .​
From this, show that it follows that the statement is true for k+1.
I.e.:
Show that ak+2 ≥ ak+1 .​
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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