Is the Sequence s_n Bounded and Monotone If x_n Is Bounded and Monotone?

  • Thread starter Thread starter rohitmishra
  • Start date Start date
  • Tags Tags
    Bounded Sequence
rohitmishra
Messages
7
Reaction score
0
Let (xn) be a seq of real nos and let sn = x1+x2+x3+...+xn / n.

prove that if if xn is bounded and monotone, then sn is also bdd and monotone.


How can i got about this one.. ?

I got it in the test today and i couldn't figure it out. only hint i could think of is how do i prove if xn is increasing because if i prove tht i can prove it. but i could not do it

please some one suggest
 
Physics news on Phys.org
You're not supposed to prove that x_n is increasing since you're basically given that x_n is either increasing or decreasing. This is what monotone means, though perhaps you would replace increasing with non-decreasing and decreasing with non-increasing if you allowed subsequent terms in the sequence to be equal to previous terms.

You need to prove two things here: 1. s_n is bounded, 2. s_n is monotone. First, to show s_n is bounded, you obviously need to use the hypothesis that x_n is bounded. What does it mean for x_n to be bounded?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top