Is the Set of Ordered Pairs of Real Numbers a Vector Space Over Reals?

Punkyc7
Messages
415
Reaction score
0
vector space?

Let v denote the set of order pairs of real numbers. If(a1,a2) and (b1,b2) are elements of V and c is an element of the reals, define (a1,a2)+(b1,b2)=(a1+b1,a2b2) and
c(a1,a2)=(ca1,a2)


is v a vector space over reals with these operations?

im thinking its not because the c only goes to a1

or because if a2=0 then there's no element in b2 that makes 1
 
Last edited:
Physics news on Phys.org


satrt by listing the vector space axioms and see if the operations satisfy them
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top