Is the Substitution Rule Applicable to Complex Numbers?

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Discussion Overview

The discussion revolves around the applicability of the substitution rule in the context of integrals involving complex numbers. Participants explore whether a substitution involving complex functions can be valid, particularly in the context of a specific integral.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant references a book stating that substitutions should operate from R to R, suggesting that substituting a complex function in the integral is inappropriate.
  • Another participant argues against this view, asserting that complex line integrals can provide a justification for using complex substitutions.
  • A different participant claims that making the substitution u = sin(t) would effectively simplify the integral, indicating that the substitution can be valid.
  • Another participant emphasizes the importance of avoiding poles in the complex plane when making substitutions, suggesting that the validity of the substitution depends on the nature of the function and the domain considered.

Areas of Agreement / Disagreement

Participants express differing opinions on the applicability of the substitution rule for complex numbers, with no consensus reached on the validity of using complex substitutions in this context.

Contextual Notes

Participants highlight the need to consider the nature of the substitution and the potential for singularities in the complex plane, indicating that the discussion is nuanced and context-dependent.

pwsnafu
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I was reading J. J. Koliha's book on analysis and came across this
It is important to bear in mind that the substitution operates from R to R; the temptation to substitute u(t) = sin t + 3i in \int_0^{\pi/2}(\sin t + 3i)^{-2} \cos t \, dt must be resisted. The right substitution is u(t) = sin t.

Do you agree?
 
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No. It's intuitively obvious to me that the answer should be 'No'. The first justification I could think of was complex line integrals and how a fundamental theorem of calculus analogue for them can be proved easily.
 
The substitution would certainly be effective in solving the integral.

If you make the substitution u=sint, then du=cost dx, so 1/(cost) du = dx

Therefore the integral simplifies to integrating (u+3i)^(-2) du.
 
Pay close attention to the quoted text. A substitution like that is indeed is only valid when your substitution is a function from ## \mathbb{R} ## to ##\mathbb{R}##.

In the complex sense, you have to be sure your substitution avoids poles (singularities) in the complex plane. For the real ##t##, ##\mathrm{sin}(t)## is never zero. That's probably not the case if ##t## were complex.
 

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