Is the Velocity Zero in Equilibrium Points of a Simple Harmonic Oscillator?

[omri3012]

Hallo,

Does the velocity i simple harmonic oscillator is zero in equilibrium points? if it's true

how does it make sense with the fact that i suppose to get a maximum kinetic

Energy in those points (stable ones)

i would really appreciate if someone could clear this issue for me.

Thanks,

Omri

 

[diazona]

The velocity of a simple harmonic oscillator is a maximum when it passes through its equilibrium point. Is that what you were asking?

 

[omri3012]

The velocity of a simple harmonic oscillator is a maximum when it passes through its equilibrium point. Is that what you were asking?

yes,

but what about the non stable equilibrium point (maximum points)?

thanks
omri

 

[JazzFusion]

Simple Harmonic Scillators have stable equilibria (or they wouldn't oscillate).

The extremes in position are not equilibrium points.

 

[omri3012]

Simple Harmonic Scillators have stable equilibria (or they wouldn't oscillate).

The extremes in position are not equilibrium points.

sorry for that... i ment that if i have a potential with maximum points does the velocity
is zero there?

 

[Bob S]

In general, the total energy of a pendulum is T + V (kinetic plus potential energy). T + V = constant. One is a maximum when the other is minimum, and vice versa. There is one other quasistable equilibrium point for a pendulum, when the pendulum is exactly upside down. In principle, it should stay there forever, barring vibration and air currents. In actually, it is unstable, because of the Heisenberg Uncertainty Principle. If the tip of the pendulum has a momentum uncertainty Δ p, and the uncertainty in position is Δ x, then the product is Δp Δx <=h/2 pi.

Based on this uncertainty (and barring friction), the pendulum will begin swinging (as I recall) in a few seconds.

Γ Δ Θ Λ Ξ Π Σ Φ Ψ Ω

 

[JazzFusion]

sorry for that... i ment that if i have a potential with maximum points does the velocity
is zero there?

If I'm understanding your question right, YES. PE is a maximum when KE is zero, and vice versa.

The farthest extent of position is the maximum of potential energy, and V is zero.