Is the Velocity Zero in Equilibrium Points of a Simple Harmonic Oscillator?

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Discussion Overview

The discussion revolves around the behavior of a simple harmonic oscillator, particularly focusing on the velocity at equilibrium points and the relationship between kinetic and potential energy. Participants explore the implications of stable and unstable equilibrium points in the context of oscillatory motion.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Technical explanation

Main Points Raised

  • Omri questions whether the velocity of a simple harmonic oscillator is zero at equilibrium points, expressing confusion about the relationship between velocity and kinetic energy at these points.
  • One participant asserts that the velocity is maximum when passing through the equilibrium point, suggesting a misunderstanding of Omri's question.
  • Omri further inquires about non-stable equilibrium points, specifically at maximum potential energy, and whether the velocity is zero there.
  • Another participant clarifies that simple harmonic oscillators have stable equilibria and that the extremes in position are not equilibrium points.
  • Omri seeks clarification on whether the velocity is zero at potential maximum points, indicating a potential misunderstanding of energy dynamics.
  • A participant discusses the total energy of a pendulum, explaining the relationship between kinetic and potential energy, and mentions a quasistable equilibrium point that is unstable due to the Heisenberg Uncertainty Principle.
  • One response confirms that at maximum potential energy, the velocity is indeed zero, aligning with the earlier discussion on energy dynamics.

Areas of Agreement / Disagreement

Participants express differing views on the nature of equilibrium points in simple harmonic oscillators, particularly regarding stable versus unstable equilibria and the behavior of velocity at these points. The discussion remains unresolved with multiple competing perspectives on the topic.

Contextual Notes

There are unresolved assumptions regarding the definitions of equilibrium points and the specific conditions under which velocity and energy relationships are discussed. The implications of potential energy maxima and their relation to velocity are not fully clarified.

omri3012
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Hallo,

Does the velocity i simple harmonic oscillator is zero in equilibrium points? if it's true

how does it make sense with the fact that i suppose to get a maximum kinetic

Energy in those points (stable ones)

i would really appreciate if someone could clear this issue for me.

Thanks,

Omri
 
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The velocity of a simple harmonic oscillator is a maximum when it passes through its equilibrium point. Is that what you were asking?
 
diazona said:
The velocity of a simple harmonic oscillator is a maximum when it passes through its equilibrium point. Is that what you were asking?

yes,

but what about the non stable equilibrium point (maximum points)?

thanks
omri
 
Simple Harmonic Scillators have stable equilibria (or they wouldn't oscillate).

The extremes in position are not equilibrium points.
 
JazzFusion said:
Simple Harmonic Scillators have stable equilibria (or they wouldn't oscillate).

The extremes in position are not equilibrium points.

sorry for that... i ment that if i have a potential with maximum points does the velocity
is zero there?
 
In general, the total energy of a pendulum is T + V (kinetic plus potential energy). T + V = constant. One is a maximum when the other is minimum, and vice versa. There is one other quasistable equilibrium point for a pendulum, when the pendulum is exactly upside down. In principle, it should stay there forever, barring vibration and air currents. In actually, it is unstable, because of the Heisenberg Uncertainty Principle. If the tip of the pendulum has a momentum uncertainty Δ p, and the uncertainty in position is Δ x, then the product is Δp Δx <=h/2 pi.

Based on this uncertainty (and barring friction), the pendulum will begin swinging (as I recall) in a few seconds.

Γ Δ Θ Λ Ξ Π Σ Φ Ψ Ω
 
omri3012 said:
sorry for that... i ment that if i have a potential with maximum points does the velocity
is zero there?
If I'm understanding your question right, YES. PE is a maximum when KE is zero, and vice versa.

The farthest extent of position is the maximum of potential energy, and V is zero.
 

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