Is There a Hidden Meaning in Integrating the Lorentz Factor with Trig Sub?

Astro Boy 327
Messages
2
Reaction score
0
Just for my own entertainment I integrated the Lorentz factor with respect to velocity, using basic trig sub, I got the equation arcsin(v/c)*(mc^2). What does this mean? Is it just useless and irrelevant in the physics world or does it have some sort of hidden meaning?
 
Physics news on Phys.org
I do not know where you got the mass from, there is no mass in the gamma factor nor in the velocity. Regardless, it does not a priori have any physical meaning to integrate the gamma factor wrt velocity.
 
Not sure what you mean by the Lorentz factor here. If I'm not mistaken you have integrated ##\int_0^v \gamma (v')mcdv'##. I'm not quite sure why you would want to do this.

Hyperbolic functions do turn up quite frequently when integrating velocities and the like in Special Relativity, which is a consequence of the structure of Minkowski space time. You might like to look up "rapidity".
 
Thread 'Can this experiment break Lorentz symmetry?'
1. The Big Idea: According to Einstein’s relativity, all motion is relative. You can’t tell if you’re moving at a constant velocity without looking outside. But what if there is a universal “rest frame” (like the old idea of the “ether”)? This experiment tries to find out by looking for tiny, directional differences in how objects move inside a sealed box. 2. How It Works: The Two-Stage Process Imagine a perfectly isolated spacecraft (our lab) moving through space at some unknown speed V...
Does the speed of light change in a gravitational field depending on whether the direction of travel is parallel to the field, or perpendicular to the field? And is it the same in both directions at each orientation? This question could be answered experimentally to some degree of accuracy. Experiment design: Place two identical clocks A and B on the circumference of a wheel at opposite ends of the diameter of length L. The wheel is positioned upright, i.e., perpendicular to the ground...
According to the General Theory of Relativity, time does not pass on a black hole, which means that processes they don't work either. As the object becomes heavier, the speed of matter falling on it for an observer on Earth will first increase, and then slow down, due to the effect of time dilation. And then it will stop altogether. As a result, we will not get a black hole, since the critical mass will not be reached. Although the object will continue to attract matter, it will not be a...
Back
Top