Is There a Problem with Two Grounds in This Simple Circuit?

[PainterGuy]

hello everyone,

can someone please help me with the problem in the circuit on the following link:-
http://img848.imageshack.us/img848/1108/groundproblem.jpg

there are two grounds (0V) (which means they can be connected to complete the circuit). don't you think there is problem with the circuit?

going counter clockwise: the voltage at "b" is 20V, at "a" 16V, and after traversing the E₁=10V, the remaining voltage is 6V. do you get my what i am trying to say? perhaps, more volts need to drop across the resistor R.

i am very grateful for any help you can give me.

cheers

 

[berkeman]

hello everyone,

can someone please help me with the problem in the circuit on the following link:-
http://img848.imageshack.us/img848/1108/groundproblem.jpg

there are two grounds (0V) (which means they can be connected to complete the circuit). don't you think there is problem with the circuit?

going counter clockwise: the voltage at "b" is 20V, at "a" 16V, and after traversing the E₁=10V, the remaining voltage is 6V. do you get my what i am trying to say? perhaps, more volts need to drop across the resistor R.

i am very grateful for any help you can give me.

cheers

The voltage at "a" is the 10V power supply's output voltage, so there is more than 4V across the resistor. Where did you get 16V?

Is this a schoolwork question? Self study?

 

[PainterGuy]

hello everyone,

can someone please help me with the problem in the circuit on the following link:-
http://img848.imageshack.us/img848/1108/groundproblem.jpg

there are two grounds (0V) (which means they can be connected to complete the circuit). don't you think there is problem with the circuit?

going counter clockwise: the voltage at "b" is 20V, at "a" 16V, and after traversing the E₁=10V, the remaining voltage is 6V. do you get my what i am trying to say? perhaps, more volts need to drop across the resistor R.

i am very grateful for any help you can give me.

cheers

The voltage at "a" is the 10V power supply's output voltage, so there is more than 4V across the resistor. Where did you get 16V?

Is this a schoolwork question? Self study?

hi berkeman,

you can say it's self-study to improve understanding. in the original i also say that there has to be more volts across the resistors. because if you start traversing the circuit from point "c" counter clockwise you get 16V at "a". do this make sense? please tell me. many thanks for your help.

cheers

 

[berkeman]

hi berkeman,

you can say it's self-study to improve understanding.

Even if for self-study, you should be posting questions like this in the HH/Intro Physics forum, and not in the General Physics forum.

in the original i also say that there has to be more volts across the resistors. because if you start traversing the circuit from point "c" counter clockwise you get 16V at "a". do this make sense? please tell me. many thanks for your help.

Then the "circuit" is labelled incorrectly. The "4V" drawn at the resistor is inconsistent with the rest of the circuit. Where did the circuit come from?

 

[PainterGuy]

Even if for self-study, you should be posting questions like this in the HH/Intro Physics forum, and not in the General Physics forum.

sorry,:shy: i am new to this forum. will learn these things soon. where to post what.

Then the "circuit" is labelled incorrectly. The "4V" drawn at the resistor is inconsistent with the rest of the circuit. Where did the circuit come from?

just made it up by using a circuit saw in a book. please tell me if the volts drawn at the resistor have been fixed then the grounds are thought to be connected to complete the circuit because both are at 0V. many thanks for teaching me this stuff.

cheers

 

[rollcast]

Get a bit of freeware called yenka and draw the circuits and it'll test them for you

 

[berkeman]

just made it up by using a circuit saw in a book. please tell me if the volts drawn at the resistor have been fixed then the grounds are thought to be connected to complete the circuit because both are at 0V.

As drawn, the circuit grounds are the same (hence connected), and the common practice is to call the voltage at the ground symbols 0V.

As drawn (forget the "4V" text), the voltage at "a" is 10V, and the voltage at "b" is 20V, so the voltage drop across the resistor is 10V.

 

[PainterGuy]

many thanks berkeman. you have really helped me. hope you will keep helping me in future.

cheers

 

[Neandethal00]

hello everyone,

can someone please help me with the problem in the circuit on the following link:-
http://img848.imageshack.us/img848/1108/groundproblem.jpg

there are two grounds (0V) (which means they can be connected to complete the circuit). don't you think there is problem with the circuit?

going counter clockwise: the voltage at "b" is 20V, at "a" 16V, and after traversing the E₁=10V, the remaining voltage is 6V. do you get my what i am trying to say? perhaps, more volts need to drop across the resistor R.

i am very grateful for any help you can give me.

cheers

4V in the resistor R is wrong.
Assuming you are taking measurement with a meter where the negative probe is at the ground.
Voltage at point 'a' is 10V (same as E1)
Voltage at point 'b' is 20V (same as E2 or E1+volts in R)
Voltage at point 'c' is 0V (ground)
Now if you move the probes between points 'a' and 'b', which is voltage in R, meter will read 10V [20-10=10V] not 4V.

You see it all depends on where you place the negative probe of the meter.

 

[PainterGuy]

many thanks Neanderthal00 for the analysis.

cheers