Is there anything more to forces than being mathematical machinery?

In summary, classical physics tells us how to compute the forces acting on a body due to another body and how different parts of the system move under the action of those forces. However, it does not provide a direct explanation of what forces are. They can be seen as a mathematical abstraction of more fundamental interactions that cause motion between particles. The concept of force may have been introduced as a means to an end in formulating laws of physics and calculating results, but there is still a lack of understanding about the true nature of forces and how they are transmitted. Some have suggested that forces may be caused by a constant agent acting according to certain laws, but the exact nature of this agent is still unknown. Ultimately, the concept of force is necessary for understanding
  • #1
etotheipi
Real forces arise between pairs of interacting bodies. For any given system, classical physics tells you how to compute the forces (i.e. Coulomb/Newton inverse square laws etc.) acting one body due to another body, and then also tells you how different parts of the system move under the action of those forces. It doesn't really tell you what the forces are though.

Really then, it appears that introducing the concept of forces is just a means to an end (i.e. you formulate your laws of physics using the construction of 'forces' and can start calculating results), since we could cut them out and just say that the interaction between particles causes motion (though admittedly it would be rather more complicated to calculate anything...). This might well be a stupid question, but is there a physical underlying motivation for introducing forces, or are they just a mathematical abstraction of the more fundamental interactions?

I'm just asking because I haven't been able to come up with a good description of what a 'force' is without referring to the definitions given the self-contained model of mechanics.

I apologise if this question has already come up before, it's one of those slightly "wishy-washy" ones that I'm sure you get a lot of but I couldn't find a satisfactory explanation for it!
 
Physics news on Phys.org
  • #2
etotheipi said:
It doesn't really tell you what the forces are though.
Why not? What would “really” tell you what they are? What does it mean to “really” tell what some X is?

etotheipi said:
I haven't been able to come up with a good description of what a 'force' is without referring to the definitions
To me, this is kind of an obvious thing. The definition of X is how we know what X is, so how could you expect to know what X is if you deliberately ignore the thing that tells you?
 
  • Like
Likes Dragrath, sophiecentaur, russ_watters and 2 others
  • #3
Dale said:
Why not? What would “really” tell you what they are? What does it mean to “really” tell what some X is?

If a particle is moving in space, I can measure its location with a set of orthogonal meter sticks for axes and build a giant arrow that I call its position vector. I can measure it's velocity (approximately) by waiting another second and then building another giant arrow, and finally by subtracting the arrows. Acceleration is the same. With lots of vector quantities, it's easy to visualise what the quantity is.

With 'force', all I can say is that I take my acceleration arrow and enlarge it by however much mass the thing has. I suppose this counts as a definition, but it's not very intuitive. It's not easy for me to pinpoint exactly what the force is, apart from that it is this multiple of the acceleration that arises because of some other thing I've put next to the particle.

Does that make any sense? It might not, I can't describe it too well (which is probably not a good sign...!).
 
  • #4
etotheipi said:
If a particle is moving in space, I can measure its location with a set of orthogonal meter sticks for axes and build a giant arrow that I call its position vector. I can measure it's velocity (approximately) by waiting another second and then building another giant arrow, and finally by subtracting the arrows. Acceleration is the same. With lots of vector quantities, it's easy to visualise what the quantity is.
All of this can be said about force. You can perform measurements to determine what the force is just as you can perform measurements for the other quantities you mention. There is no difference whatsoever.

etotheipi said:
It's not easy for me to pinpoint exactly what the force is
That is probably because you are ignoring the definition. The definition of X is the thing that tells you what X is. How can you expect to know what something is “without referring to the definition“?
 
  • Like
Likes sophiecentaur, russ_watters and etotheipi
  • #5
At a fundamental level you might start to ask what space and time really are, but the question about forces is more to the point. Newton was well aware that although his law of gravitation explained the motion of the planets, for example, there was no rational mechanism for this force:

It is inconceivable that inanimate Matter should, without the Mediation of something else, which is not material, operate upon, and affect other matter without mutual Contact…That Gravity should be innate, inherent and essential to Matter, so that one body may act upon another at a distance thro' a Vacuum, without the Mediation of any thing else, by and through which their Action and Force may be conveyed from one to another, is to me so great an Absurdity that I believe no Man who has in philosophical Matters a competent Faculty of thinking can ever fall into it. Gravity must be caused by an Agent acting constantly according to certain laws; but whether this Agent be material or immaterial, I have left to the Consideration of my readers.[5]
— Isaac Newton, Letters to Bentley, 1692/3
The electromagnetic force in the classical theory has the same issue. If we say that all classical forces are either gravitational or electromagnetic, then quite explicity we know how to measure a force and how to model it, but the theories say nothing about how that force is transmitted. Or "what it really is".
 
  • Like
Likes Marc Rindermann, Shirish, Dragrath and 4 others
  • #6
etotheipi said:
This might well be a stupid question, but is there a physical underlying motivation for introducing forces, or are they just a mathematical abstraction of the more fundamental interactions?
Maybe I'm not understanding your dilemma, but one underlying motivator for the concept of force is the relative difficulty of lifting an object and moving it to some other place. One factor would be the object's weight. For example, my house is situated near a stream. About 14,000 years ago, my property was covered by a layer of ice maybe 2,000 ft. thick. As the ice moved downstream, it carried rocks of all sizes with it, but when the ice melted away, the rocks were left in place. As a result, there are rocks of all sizes here an there on my property. Most of these are of a size that I can lift, but I've found one that was too heavy for me to lift, and there's another huge boulder that would be too heavy for anything but a high-capacity crane to lift.

My point is that the weight of an object, the force of attraction between the Earth and the object, is anything but a mere mathematical abstraction.
 
  • Like
Likes Saph, gmax137 and etotheipi
  • #7
I think that you are asking if the abstraction of "force" is essential. The abstraction allows it to be used in many situations that would not fit anyone specific non-abstract definition.
 
  • Like
Likes etotheipi
  • #8
...I have left to the Consideration of my readers

Newton falling for the old "I have left [insert impossibly difficult thing] as an exercise to the reader" trap...
PeroK said:
If we say that all classical forces are either gravitational or electromagnetic, then quite explicity we know how to measure a force and how to model it, but the theories say nothing about how that force is transmitted. Or "what it really is".

That's fair enough, it's sort of what I'd presumed was the resolution. Just a directed line segment associated with the interaction of one body on another in such a way that you get ##\mathbf{F} = m\mathbf{a}##, in classical physics anyway. The interaction is real, the force is just a way of modelling it, which I guess makes it just as real too.

I know essentially nothing about relativistic theories since I have barely studied them, but I am aware that in that arena you get ##\mathbf{F} = \gamma^{3} m\mathbf{a}##. I presume in that definition it is the acceleration that changes and not the force (i.e. all that strange coordinate/proper stuff). Muddies the water a little bit in terms of defining what a force is, but I don't really want to go down that road since I don't know enough for it to be meaningful...
 
  • #9
etotheipi said:
Just a directed line segment associated with the interaction of one body on another in such a way that you get ##\mathbf{F} = m\mathbf{a}##, in classical physics anyway.
But even there, what about the situation where there are two opposing "forces" giving no actual acceleration? ##F=mA## works as a definition of net force, but there is a lot of use of forces that are opposed and result in no acceleration.
 
  • Like
Likes etotheipi
  • #10
FactChecker said:
But even there, what about the situation where there are two opposing "forces" giving no actual acceleration? ##F=mA## works as a definition of net force, but there is a lot of use of forces that are opposed and result in no acceleration.

Yeah, I guess the additional stipulation that it's the only force for the purposes of the definition is needed.

Thanks for your replies, I just thought it was slightly curious. At the end of the day classical physics is just a model that happens to be fairly consistent with observation and the nature of the forces themselves don't really matter, just so long as they're consistent with the model. I suppose you could say the same thing about energy or indeed any physical quantity, as @Dale alluded to.
 
  • #11
PeroK said:
If we say that all classical forces are either gravitational or electromagnetic, then quite explicity we know how to measure a force and how to model it, but the theories say nothing about how that force is transmitted. Or "what it really is".
I disagree. When a theory defines X that is the theory explicitly saying what X is.

I categorically dislike questions containing the word “really”. If you ask “what is force” people simply respond (correctly) with the definition. Ask “what is force really” and suddenly everyone is afraid to respond (correctly) with the definition. The word “really” does not change the answer.
 
Last edited:
  • Like
Likes nasu, russ_watters, Saph and 2 others
  • #12
Dale said:
I disagree. When a theory defines X that is the theory explicitly saying what X is.

I like that quotation from Newton because it shows that he knew there must be something more fundamental going on. The popular picture is often of this great man who thought he had explained everything and who would have been horrified by GR. However, given what he said about his own theory, if you brought him back in 1915 and showed him GR I imagine he would have said "I knew there was more to it"!
 
  • Like
Likes Dragrath, Saph, Dale and 1 other person
  • #13
Dale said:
I categorically dislike questions containing the word “really”. If you ask “what is force” people simply respond (correctly) with the definition. Ask “what is force really” and suddenly everyone is afraid to respond (correctly) with the definition. The word “really” does not change the answer.

I do apologise, that wasn't the intent of my OP! If the best answer is that force is a quantity defined as ##m\mathbf{a}##, I would consider that a perfectly good answer. Since in the context of the OP, the conclusion would be that, yes, force is a mathematical construction (i.e. it arises from a precise mathematical definition). If instead it were the case that force had another underlying interpretation that I wasn't aware of, and that it was solely modelled by ##m\mathbf{a}## in classical mechanics, that would contradict the title and be another answer.

I've no issues with the definitions within the confines of Newtonian mechanics, was just interested to see if anyone knew something cool that I was unaware of :smile:.
 
  • #14
Dale said:
I categorically dislike questions containing the word “really”.

Me too.

Dale said:
Ask “what is force really” and suddenly everyone is afraid to respond (correctly) with the definition. The word “really” does not change the answer.

Ah, but what is it really really? :devil:

The thing i don't like the word "really" is that it allows the OP of a thread to think he is asking a clear question when in fact he or she is not. The subtext is usually "I know the definition, but am dissatisfied with it in some way", which is fine, but by allowing the "really" construct, it leaves the responders guessing as to what the concern really is.
 
  • Like
Likes nasu, Dale and etotheipi
  • #15
I can't claim to have read Newton's mind, but I like to think that he invented forces as part of a method for understanding the universe. What happened is probably something like this. Newton looked at the universe around him and thought, "I can't understand this all at once. I need to chop it up into little pieces, study each piece separately, reassemble the pieces and with some luck and educated guesses I will reach new insights about how the pieces work together."

Of course when studying each piece (now called "the system") you cannot really separate it from the others because they affect it. So if you want to ignore the rest of the universe and concentrate on the system, you have to replace the effects of the universe on the system with something that mimics these effects. That particular something is a "force", sometimes exemplified by the disembodied hand often seen in physics textbooks. That kind of reasoning was, I think, the motivation for the genesis of the Newtonian idea of force. The first and third laws follow directly from this idea. First law: "If you leave it alone, it will keep on doing what it has always been doing". Thirdlaw : "If you let it know that you are there, it let's you know that it is there." The second law is just a quantification of the effect that the sum of all the forces has on a system.

So to me, a force is a mode of interaction of a system with the rest of the universe. If the universe exerts no forces (not zero net force) on the system, the system does not know that the universe exists and neither does the universe know that the system exists. We deduce the existence of forces by examining the motion of objects after having postulated that objects change their state of motion because of forces.
 
  • Like
  • Love
Likes Delta2, Dale and etotheipi
  • #16
Vanadium 50 said:
The thing i don't like the word "really" is that it allows the OP of a thread to think he is asking a clear question when in fact he or she is not. The subtext is usually "I know the definition, but am dissatisfied with it in some way", which is fine, but by allowing the "really" construct, it leaves the responders guessing as to what the concern really is.

I was hesitant to start the thread precisely for this reason, I couldn't really articulate it well at all which makes it hard for you guys to help out. So I am sorry, I'll try to steer clear of open-ended questions like this in the future.

That said, all of the replies are genuinely helpful so thank you everyone for putting up with me :smile: !
 
  • Like
Likes Dale
  • #17
etotheipi said:
I'm just asking because I haven't been able to come up with a good description of what a 'force' is without referring to the definitions given the self-contained model of mechanics.
There are only experiments and mathematical models that describe\predict them. No metaphysical entities of forces or any other physical constructions exist
 
  • Like
Likes etotheipi
  • #18
etotheipi said:
If the best answer is that force is a quantity defined as ##m\mathbf{a}##, I would consider that a perfectly good answer.

Force is defined as something that needs to be impressed upon a body to change its state of rest or uniform motion. Newton never specified the nature of force - e.g. if it is "material or immaterial" (see citation in #5). There was no reson to do so. That would just raise philosophical discussions without any benefit.

The original second law is btw. not F=m·a but F=dp/dt. That still holds in special relativity.
 
  • Like
Likes Marc Rindermann, Delta2, FactChecker and 1 other person
  • #19
etotheipi said:
At the end of the day classical physics is just a model that happens to be fairly consistent with observation and the nature of the forces themselves don't really matter, just so long as they're consistent with the model.

The thing is, though, scientists, engineers, and technicians can use the concept to do stuff and to build stuff. That is where the value really lies, in the utility of the concept.
 
  • Like
Likes etotheipi
  • #20
For a total layman's perspective with grade 8 mathematics, isn't force 'really' just how much something pushes on something? Or pushes back, if stationary?
 
  • #21
You should probably say that force is F=mA or that force is the ability to cause acceleration of a mass. That gives it units and a way to specify the amount even if there is an opposing force that stops any acceleration.
 
  • #22
The ability to cause acceleration of another mass or of the mass in question who's force we are measuring?
 
  • #23
apollo said:
The ability to cause acceleration of another mass or of the mass in question who's force we are measuring?
We evaluate a force based on the acceleration of the thing that it acts on.$$\sum F=ma$$The ##\sum F## is the sum of all forces that act on the object whose mass is ##m##. The acceleration of that object will be ##a##.

If we are talking about a pair of objects pushing or pulling on one another, Newton's third law tells us that the force of the one on the other will be equal to that of the other on the one. So it does not matter much which object we use to determine how much force there is. Use the one that makes for the easiest measurement.
 
  • #24
apollo said:
For a total layman's perspective with grade 8 mathematics, isn't force 'really' just how much something pushes on something? Or pushes back, if stationary?
There's no need for the "if stationary" caveat.

I don't think there's any such thing as a total layman's perspective. There's a degree to which any concept can be understood, and sometimes it can go very shallow, but only if it leaves out something that might be important..
 
  • #25
Mister T said:
There's no need for the "if stationary" caveat.
I think the point is that the absence of acceleration does not always imply the absence of any force. It would be nice if the definition of force did not require an actual acceleration.
The definition of force does not really require an actual acceleration:
From https://en.wikipedia.org/wiki/Force: "a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity (which includes to begin moving from a state of rest), i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity. It is measured in the SI unit of Newtons and represented by the symbol F. "
 
Last edited:
  • Like
Likes Delta2 and etotheipi
  • #26
FactChecker said:
It would be nice if the definition of force did not require an actual acceleration.

It doesn't. The definition of forces says that they are proportioanl (or equal if you use proper units) to change of momentum. If you have a force acting on a body it changes it's momentum by ##\dot p##. If there is another force that changes its momentum by ##-\dot p## than there is no acceleration, even though both forces comply with Newton II and would result in an acceleration if they would act alone. You can also calculate the individual accelerations and add them to get the total acceleration of the body. However, I prefer adding the forces in order to get the acceleration as described by jbriggs444 in #23 above.
 
  • #27
DrStupid said:
If you have a force acting on a body it changes it's momentum by ##\dot p##. If there is another force that changes its momentum by ##-\dot p## than there is no acceleration,

That's actually quite an interesting take on it, since I've only really ever considered the ##\dot{p}## due to the resultant force. I suppose you could think of it in terms of each force pumping in or siphoning out momentum, and just adding together all of the changes.
 
  • Like
Likes Marc Rindermann
  • #29
DrStupid said:
It doesn't. The definition of forces says that they are proportioanl (or equal if you use proper units) to change of momentum. If you have a force acting on a body it changes it's momentum by ##\dot p##.
The problem with requiring any actual change of momentum is the same as the problem with requiring an actual acceleration. That does not always happen.
If there is another force that changes its momentum by ##-\dot p## than there is no acceleration,
If there is no change of momentum then your definition gives no force of any kind.

Your original statement "Force is defined as something that needs to be impressed upon a body to change its state of rest or uniform motion. " is one that, without explicitly stating it, does not require that there actually be a "change of state of rest or uniform motion", just that it "needs to be impressed" to make such a change. That is a distinction which only obsessive/compulsive people might care about. (I plead guilty.)
 
Last edited:
  • Like
Likes etotheipi
  • #30
I think @DrStupid's suggestion was taking a principle of superposition approach; i.e. if ##\vec{F}_1 = \dot{p}_1##, ##\vec{F}_2 = \dot{p}_2## when acting individually then ##\vec{F}_1 + \vec{F}_2 = m(\dot{v}_1 + \dot{v}_2) = \dot{p}_t##. Since the accelerations and rate of change of momenta are linear in force, it's valid to consider each action individually and then superpose them at the end.

Whilst of course the physical law is that the resultant force is ##\frac{d\vec{p}}{dt}##.
 
  • #31
etotheipi said:
I think @DrStupid's suggestion was taking a principle of superposition approach; i.e. if ##\vec{F}_1 = \dot{p}_1##, ##\vec{F}_2 = \dot{p}_2## when acting individually then ##\vec{F}_1 + \vec{F}_2 = m(\dot{v}_1 + \dot{v}_2) = \dot{p}_t##. Since the accelerations and rate of change of momenta are linear in force, it's valid to consider each action individually and then superpose them at the end.

Whilst of course the physical law is that the resultant force is ##\frac{d\vec{p}}{dt}##.
Yes, I agree. I am afraid that I was getting obsessed with a detail and should leave it alone.
 
  • #32
FactChecker said:
Yes, I agree. I am afraid that I was getting obsessed with a detail and should leave it alone.

No I think your objection was quite valid, since there wasn't an explicit mention of superposing solutions. I also agree that I find the definition of forces slightly unsatisfying, but it appears to be the case that we can't do much better :frown:.
 
  • #33
etotheipi said:
I suppose you could think of it in terms of each force pumping in or siphoning out momentum, and just adding together all of the changes.

That's exactly how I see it. Force is an exchange of momentum between two systems. That implies both Newton II and Newton III. The energy equivalent would be the power of work and heat. According to the first law of thermodynamics the sum of work and heat transferred to a system is equal to the change of its internal energy. But that does not mean that there is no work or heat if the internal energy remains constant.
 
  • Like
  • Informative
Likes Marc Rindermann, jbriggs444 and etotheipi
  • #34
FactChecker said:
Your original statement "Force is defined as something that needs to be impressed upon a body to change its state of rest or uniform motion. " is one that, without explicitly stating it, does not require that there actually be a "change of state of rest or uniform motion", just that it "needs to be impressed" to make such a change.

I am quite sure that it is ment like that because Newton repeated it in the first law of motion. A force is required to change the state of motion but it is not sufficient. Several forces and the corresponding changes of momentum (and therefore also the resulting accelerations) can add to zero.
 
  • Like
Likes FactChecker
  • #35
DrStupid said:
That's exactly how I see it. Force is an exchange of momentum between two systems. That implies both Newton II and Newton III. The energy equivalent would be the power of work and heat. According to the first law of thermodynamics the sum of work and heat transferred to a system is equal to the change of its internal energy. But that does not mean that there is no work or heat if the internal energy remains constant.

That's certainly a nice way of thinking of it!
 

Similar threads

  • Classical Physics
Replies
29
Views
2K
Replies
4
Views
1K
Replies
13
Views
968
  • Classical Physics
2
Replies
61
Views
1K
  • Classical Physics
Replies
6
Views
619
  • Classical Physics
Replies
30
Views
3K
Replies
35
Views
3K
Replies
10
Views
2K
Replies
86
Views
4K
Replies
5
Views
573
Back
Top