Is There Enough Information to Solve the Relativistic Velocity Addition Problem?

AI Thread Summary
The discussion centers on solving the relativistic velocity addition problem involving two asteroids approaching each other at a relative speed of 0.5c, as observed from Europa. The initial confusion arises from the interpretation of the problem statement and the application of the relativistic velocity addition formula. It is clarified that there is no ambiguity; asteroid A moves at +v and asteroid B at -v relative to Europa. The correct approach confirms that the velocity of asteroid B in the rest-frame of asteroid A is -c/2, resolving the misunderstanding. The discussion emphasizes the importance of correctly applying signs and understanding frame references in relativistic calculations.
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Homework Statement


Two asteroids are approaching one another moving with the same speed speed as measured from a stationary observer on Europa. Their relative speed is 0.5c. Find the speed of one of asteroids relative to Europa.

I understand how relativistic velocity addition works but am not able to solve this question. Is it possible there is not enough information given in the problem? Any help would be much appreciated.

Homework Equations


u = (u' + v) / (1 + (u'v)/c^2)

The Attempt at a Solution


The ambiguity of the problem statement has led me down several different paths each resulting in a quadratic that in most cases results in a speed faster than c.
 
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You might find the following form of the equation easier to understand.

Relativistic addition of velocities:
V_{a/c} = \frac{V_{a/b} + V_{b/c}}{1 + (V_{a/b} V_{b/c})/c^2}

Hint: Let "b" be Europa. ("a/c" means the velocity of "a" as measured in the frame of "c".)
 
Assuming "b" is Europa I would let V(a/c) be the speed of Ship A relative to Ship B which we know to be 0.50c. By the problem statement we have V(a/b) = V(b/c) = V(c/b) = V'. Thus we have 0.50c = 2V' / (1 + (V'^2/c^2)). This leads to a quadratic which I was told is the incorrect approach. Was that incorrect advice? Thank you very much for your help.
 
mfreeman said:
Assuming "b" is Europa I would let V(a/c) be the speed of Ship A relative to Ship B which we know to be 0.50c.
To keep your sanity, let "a" stand for asteroid #1 and "c" stand for asteroid #2. Furthermore, let asteroid "a" move to the right and "c" move to the left. (As seen from Europa.)

mfreeman said:
By the problem statement we have V(a/b) = V(b/c) = V(c/b) = V'.
Careful! Signs matter. Let "to the right" be positive.
 
mfreeman said:
Thus we have 0.50c = 2V' / (1 + (V'^2/c^2)).
Actually, this equation looks fine to me.
 
Gosh I thought so! Thanks.
 
mfreeman said:
Gosh I thought so! Thanks.
Good!

Just for the record, if V(a/b) = V', then V(b/a) = - V'.
 
mfreeman said:

Homework Statement


Two asteroids are approaching one another moving with the same speed speed as measured from a stationary observer on Europa. Their relative speed is 0.5c. Find the speed of one of asteroids relative to Europa.

I understand how relativistic velocity addition works but am not able to solve this question. Is it possible there is not enough information given in the problem? Any help would be much appreciated.

Homework Equations


u = (u' + v) / (1 + (u'v)/c^2)

The Attempt at a Solution


The ambiguity of the problem statement has led me down several different paths each resulting in a quadratic that in most cases results in a speed faster than c.

There is no ambiguity. Relative to Europa, asteroid A moves at velocity +v and asteroid B at velocity -v. You are given that the velocity of B in the rest-frame of A is -c/2.
 
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