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Is this a simple circle, with radius 1/2?

  1. Mar 1, 2010 #1
    I'm trying to understand this expression:
    [tex]y=x^2+y^2[/tex]

    Using wolfram alpha it tells me this is a circle of radius 1/2

    But to me I'm unfamiliar with this way of setting up a circle. Specifically the y on both sides of the equation is troubling me. How would you interpret it? Would you reduce it somewhat before interpreting it?
     
  2. jcsd
  3. Mar 1, 2010 #2

    Dick

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    I would write it as 0=x^2+y^2-y and complete the square in y.
     
  4. Mar 1, 2010 #3
    Completing the square worked perfectly. Thank you.
     
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