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**1.Set up the integral to Find the volume enclosed by the cylinder x^2 +y^2 = 1 x=0 and z=y**

**3. The area to integrate over is the part of x^2 + y^2 =1 above the x axis. X goes from -1 to 1 and y goes from 0 to sqrt(1-x^2) So the integral should be:**

[tex] \int^1_{-1} \int^{\sqrt(1-x^2)}_0 y dy dx [/tex]

[tex] \int^1_{-1} \int^{\sqrt(1-x^2)}_0 y dy dx [/tex]