Is uniform electric field realistic?

AI Thread Summary
The discussion centers on the concept of a uniform electric field, particularly in relation to Gauss's law and its application to charged planes and conductors. It is established that while the expression E = σ/2ε for an infinite plane suggests a constant electric field, this is an approximation, as uniform fields do not exist in reality. The electric field near a conductor's surface is accurately described by σ/ε, but this too is an approximation that changes with distance from the surface. Numerical methods can be employed to calculate fields in non-ideal configurations, though deriving precise values mathematically can be complex. Overall, the conversation emphasizes the limitations of theoretical models in accurately representing real-world electric fields.
Axe199
Messages
47
Reaction score
0
I was learning about gauss's law and how to use to determine electric field, one of them is an infinite plane of continuous and uniform charge , eventually E= σ/2ε which means the E is not depend on the distance from the plane , does that mean anywhere i place a test charge above this plane it will experience the same force? can this happen in reality? or is it just a mathematical term?
 
Physics news on Phys.org
A uniform field for all space and all time is impossible, as it doesn't exist here and now. So it's an approximation. Like frictionless planes, stretchless ropes, massless pulleys, etc. That said, it cvan be a useful approximation.
 
Vanadium 50 said:
A uniform field for all space and all time is impossible, as it doesn't exist here and now. So it's an approximation. Like frictionless planes, stretchless ropes, massless pulleys, etc. That said, it cvan be a useful approximation.
what about metal they have a similar expression of the E , is that an approximation too? if yes , can we get the real number mathematically or just experimentally?
 
I don't understand what you are saying.
 
In the case of two oppositely charged plates (capacitor), the field between the two plates sufficiently inside the outer edges of the plates is a close approximation to a field of constant intensity.
 
Vanadium 50 said:
I don't understand what you are saying.

i meant if we have a conductor , the field expression is σ/ε is this an approximation too?
if it's an approximation , is there a mathematical way to derive an accurate answer ? or the field is determined accurately at a certain point only by experiment?
 
Axe199 said:
i meant if we have a conductor , the field expression is σ/ε is this an approximation too?
if it's an approximation , is there a mathematical way to derive an accurate answer ? or the field is determined accurately at a certain point only by experiment?

You mean for a finite sized charged plate? The field very near the center of the plate will be approximately the expression given. As you get farther from the plate and or closer to the edges the fields will become very different. The strengths as well as directions will change as well. But it's very hard to mathematically derive the fringe fields from first principles because the geometry is too complicated.
 
There are numerical methods for calculating the field (at least to some level of approximation) in a non-ideal configuration. If you have a specific configuration in mind, someone here might be able to tell you which is the most appropriate method for that configuration.
 
Axe199 said:
i meant if we have a conductor , the field expression is σ/ε is this an approximation too?
if it's an approximation , is there a mathematical way to derive an accurate answer ? or the field is determined accurately at a certain point only by experiment?

The electric field has magnitude \frac{\sigma}{\epsilon_0} only at the surface of the conductor. It might change as you move away from the surface. This expression comes about from assuming that charge smoothly spreads out across the conductor's surface (and that Gauss's law is valid). Of course, charges come in clumps (electrons, etc.) so it's not smooth. So yes, it is an approximation... but a good one.
 
  • #10
jtbell said:
There are numerical methods for calculating the field (at least to some level of approximation) in a non-ideal configuration. If you have a specific configuration in mind, someone here might be able to tell you which is the most appropriate method for that configuration.

i have a certain setup in mind, for example , the electric field 1 m above the top of a van de graaff generator
 
  • #11
ZetaOfThree said:
The electric field has magnitude \frac{\sigma}{\epsilon_0} only at the surface of the conductor. It might change as you move away from the surface. This expression comes about from assuming that charge smoothly spreads out across the conductor's surface (and that Gauss's law is valid). Of course, charges come in clumps (electrons, etc.) so it's not smooth. So yes, it is an approximation... but a good one.
electrons comes in clumps even in conductors like metals ?
 
  • #12
Axe199 said:
electrons comes in clumps even in conductors like metals ?

Yeah. "Clump" is my colloquial term for "particle". Electrons are particles.
 
  • #13
ZetaOfThree said:
Yeah. "Clump" is my colloquial term for "particle". Electrons are particles.

okay then , i thought clumps means something like lumps
 

Similar threads

Replies
2
Views
828
Replies
3
Views
2K
Replies
1
Views
1K
Replies
2
Views
1K
Replies
5
Views
3K
Replies
1
Views
1K
Replies
3
Views
1K
Back
Top