Is x^2>9 true if and only if x is not equal to 2?

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The discussion revolves around determining the correct logical connector between the statements "x > 2" and "x^2 > 9." Participants explore whether to use "if," "only if," or "if and only if," concluding that none of these options fit due to the lack of constraints on x. They clarify that while x^2 > 9 is true for x < -3 or x > 3, x > 2 does not necessarily imply x^2 > 9. Ultimately, it is agreed that the only necessary condition is that x cannot equal 2, and neither x > 2 nor x < -3 are sufficient for x^2 > 9. The discussion emphasizes the importance of understanding necessary and sufficient conditions in logical statements.
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Homework Statement



Insert either "if", "only if", or "if and only if"..

x>2 ... x^2>9

Homework Equations





The Attempt at a Solution



I don't think any fit :S coonffuuuuuused
 
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x can be any real number? In that case I *think* it should be "if".
But I'm no expert at this :P
 
if equals =>
only if equals <=
if and only if equals <=>
 
Trail_Builder said:

Homework Statement



Insert either "if", "only if", or "if and only if"..

x>2 ... x^2>9

Homework Equations





The Attempt at a Solution



I don't think any fit :S coonffuuuuuused

One fits perfectly. Think about what dirk said.
 
Oops sorry, guess I was wrong.
 
still don't know :S

I know the x^2>9 is equivalent to x<-3 or x>3.

so I am guessing that rules out the <=>

and if it was the x>3, then I would stick the <= one in. ("only if").

"if" obviously won't work.

but don't you have to consider the x<-3 case too? or am I imposing somekind of weird necessary/sufficient crap in where i shouldn't?
 
Trail_Builder said:
still don't know :S

I know the x^2>9 is equivalent to x<-3 or x>3.

so I am guessing that rules out the <=>

and if it was the x>3, then I would stick the <= one in. ("only if").

"if" obviously won't work.

but don't you have to consider the x<-3 case too? or am I imposing somekind of weird necessary/sufficient crap in where i shouldn't?

Ponder the following. First, assume that x>2 is true. Does this imply that x^2>9 is true? If yes, then "if x>2, then x^2>9". If no, then not "if x>2, then x^2>9". (This is the "sufficient" condition.) Second, assume that x^2>9 is true. Does this imply that x>2 is true? If yes, then "only if x>2, then x^2>9". If no, then not "only if x>2, then x^2>9". (This is the "necessary" condition.) If yes to both, then "if and only if".
 
Don't you also need to insert 'then' somewhere? :smile:
 
Trail_Builder said:
but don't you have to consider the x<-3 case too? or am I imposing somekind of weird necessary/sufficient crap in where i shouldn't?

I think you need to know if there are any constraints on x. Can it be only a positive integer, perhaps? What does it say in your book?
 
  • #10
_Andreas said:
Ponder the following. First, assume that x>2 is true. Does this imply that x^2>9 is true? If yes, then "if x>2, then x^2>9". If no, then not "if x>2, then x^2>9". (This is the "sufficient" condition.) Second, assume that x^2>9 is true. Does this imply that x>2 is true? If yes, then "only if x>2, then x^2>9". If no, then not "only if x>2, then x^2>9". (This is the "necessary" condition.) If yes to both, then "if and only if".

thanks for the clarification. I kind just used my intuition before but glad to know how to properly do it, lol :).

the answer is no and no then, because there isn't a constaint on x... :S

so was I right in saying none?
 
  • #11
_Andreas said:
I think you need to know if there are any constraints on x. Can it be only a positive integer, perhaps? What does it say in your book?

no specified constaints
 
  • #12
Trail_Builder said:
thanks for the clarification. I kind just used my intuition before but glad to know how to properly do it, lol :).

the answer is no and no then, because there isn't a constaint on x... :S

so was I right in saying none?

Yeah, if there are no constraints on x, then it seems to me that you were correct in that none fit. It is not necessary that x>2 for x^2>9. What's necessary is that x is not equal to 2. Neither is x>2 sufficient for x^2>9. (In other words I was wrong when I said one fits perfectly.)
 
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