Is Your Solution to the Limit Problem Correct?

[transgalactic]

<br /> lim_{x-&gt;\infty}\frac{3x-cosx}{4x+sinx}=lim_{x-&gt;\infty}\frac{\frac{3x-cosx}{x}}{\frac{4x+sinx}{x}}=lim_{x-&gt;\infty}\frac{3-0}{4-0}=0.75 <br />

i thought bounded/infinity=0


??

 

[Mark44]

You have the correct limit, but you should remove the limit operator from the expression below, since you have already "passed to the limit" in the previous expression:
lim_{x-&gt;\infty}\frac{3-0}{4-0}=0.75

 

[transgalactic]

thanks