Isothermal compression of monatomic gas ?

AI Thread Summary
The discussion revolves around solving a homework problem involving the isothermal compression of a monatomic ideal gas. The initial conditions include 5 moles of gas at a volume of 0.50 m³ and a pressure of 2.0 x 10^5 Pa, which is compressed to a final volume of 0.20 m³. Participants clarify that the ideal gas law (pV = nRT) is the key to finding the final pressure, emphasizing that temperature remains constant and can be eliminated from the equations. The final pressure can be calculated using the relationship p1V1 = p2V2, leading to the formula p2 = p1V1/V2. The conversation highlights the simplicity of the problem once the correct approach is identified.
zaf
Hello forum members

I need some help on H.W problem...just enough reasoning to atleast get started

the question is as follows:
5 moles of a monoatomic ideal gas at an initial volume of .50 m^3 and an initial pressure of 2.0 * 10^5 Pa undergoes an isothermal compression to .20m^3. Find the final pressure ?

so, the temperature is going to be constant , the inital and final volumes and intial pressure is also know, also the total energy (Q)is going to be work done on the gas... which must be negaive... internal energy is conserved ? am i correct so far...how do i solve this ?
 
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You're overcomplicating. The energy doesn't figure into it. It is also irrelevant that the gas is monatomic. The problem is much easier than you suspect.


Njorl
 
Right Njorl,
all there is to use is the equation of an ideal gas:
pV = nRT.
Since there is initial & final state, it's a system of 2 equations:
I) p1V1 = nRT
II) p2V2 = nRT
Now, T is not given, so you better eliminate it:
I) T = p1V1/nR
II) T = p2V2/nR
Which are clearly equal, so
I = II) p1V1/nR = p2V2/nR
or (nR cancels)
p1V1 = p2V2
And we solve for p2:
p2= p1V1/V2
OK?
 
Yes, but I thought it should be left for Zaf to do with just the hint.

Njorl
 
yes. i understand arcnets... thank you
 
Originally posted by Njorl
Yes, but I thought it should be left for Zaf to do with just the hint.

Njorl
Yes, right. Maybe that was a little too much...
 
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