Hi to all.
I run a rapid back of the envelope calculation on the CS137 quantity TEPCO estimated.
If I got it right from Wolfram Alpha the activity of CS137 is 3.214 TeraBq/gram.
Having TEPCO estimated overall CS137 at 720,000 TeraBq, that would lead to 720,000/3.214=224,020 grams of CS137.
I then tried to understand in what relation that value is in respect to the total CS137 inventory that can be expeced from 1,2,3 cores.
I know this has been much more accurately estimated somewhere before in this 3d but I unfortunately do not have the possibility of searching the whole discussion right now.
However from wiki I got a fission yield of 6.0899% for CS137. That yield together with the mass ratio of U235 vs CS137 leads me to estimate in about 6.26 tonns the amount of U235 that has to undergo fission to pruduce this amount of CS137 (224,020/0.060899*235/137 grams).
Now if I remeber correctly at 32% of thermal efficiency 1 tonn of U235 has to undergo fission to produce 1 Gigawatt for one year.
Being almost exactly 2 gigawatts the overall power output of the concerned units, it would seem that the estimated CS137 already in the water is in the order of magnitude of 3 yrs worth of fission process.
In other words that would lead me to think that this estimates means that much of the molten fuel is already soluted in water.
On the other hand this conclusion, in a way reassuring, seems unreaalistic to me.
what I am I doing wrong ?
what do you think ?
thanks in advance