Joint and conditional distributions

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Discussion Overview

The discussion revolves around evaluating the joint and conditional distributions of two independent Chi-square random variables, X and Y, with different degrees of freedom. The specific problem involves calculating the probability P(X>a, X-Y>0) and exploring the implications of conditional probabilities in this context.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant seeks to evaluate P(X>a, X-Y>0) using Bayes' theorem, expressing it in terms of conditional probabilities.
  • Another participant suggests that the condition can be simplified to P(X>a, X>Y) = P(X>max{a,Y}), noting that this changes based on the relationship between a and Y.
  • A participant questions the necessity of the conditional probability formula and points out that the evaluation hinges on the random nature of Y.
  • There is a discussion about the lack of a set threshold for determining when P(X>a,X>Y) transitions from P(X>a) to P(X>Y), emphasizing the randomness of Y.
  • One participant proposes that the cumulative distribution function (CDF) of max{a,Y} could be a linear combination of CDF(Y|Y>a) and the mass point Y=a, but acknowledges the complexity of further evaluating the related random variable.

Areas of Agreement / Disagreement

Participants express differing views on the approach to evaluating the conditional probabilities and the implications of the random variable Y. There is no consensus on a definitive method for calculating P(X>a,X>Y) or establishing a threshold.

Contextual Notes

Participants note the dependence on the random variable Y and the implications for evaluating the maximum function, indicating that the problem is complex and lacks straightforward resolution.

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I'm having a problem evaluating a distribution-

Suppose X and Y are Chi-square random variables, and a is some
constant greater than 0. X and Y are independent, but not identically distributed (they have different DOFs).
I want to find

P(X>a,X-Y>0). So I use Bayes' theorem to write

P(X>a,X-Y>0)
=P(X>a | X-Y > 0)*P(X-Y>0)
=P(X>a| X>Y)*P(X>Y)

Now I have an expression for P(X>a) and P(X>Y), but I am at a
loss as to how to evaluate the conditional distribution P(X>a|
X>Y).

I figured out that if Y was a constant (rather than a random variable), then I could write

P(X>a| X>Y) = { 1 if Y>a
{ P(X>a)/P(X>Y) if Y<a

But this does not help evalaute the distribution because I requires knowledge of the value of random variable Y.

Any help will be much appreciated.
 
Last edited:
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Why are you going through the conditional probability formula?

(X>a, X>Y) if and only if (X > max{a,Y}) or (X - max{a,Y} > 0). Just an observation.
 
Why are you going through the conditional probability formula?
(X>a, X>Y) if and only if (X > max{a,Y}) or (X - max{a,Y} > 0). Just an observation

Thanks, that is a good observation. So now I know that

P(X>a,X>Y) = P(X>max(a,Y)). I would like to express this as some function of P(X>a) and P(X>Y) . That is, I know that

P(X>a,X>Y) = [ P(X>a) if a>Y
[ P(X>Y) if a<Y

but I only know a, not Y (since Y is an RV). So, in other words, is there a way to determine the 'threshold' at which P(X>a,X>Y) changes from P(X>a) to P(X>Y)?
 
BTW, is this homework? If it is, this is not the place to post it.

There is no set threshold because -- as you posted -- Y is a r.v. By implication so is max{a,Y}. I am guessing that the cdf of max{a,Y} would be some linear combination of CDF(Y|Y>a) and the mass point Y=a (representing all the occurances of Y<a). Even after obtaining CDF(max{a,Y}) you still need to figure out the CDF of the related r.v. (X - max{a,Y}).
 

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