Ted123 Messages 428 Reaction score 0 Thread starter Nov 10, 2011 #1 In both cases the algebraic multiplicty is 7, minimal and geometric multiplicities are both 3. Why does this mean knowing these multiplicies is not enough to deduce the Jordan normal form?
In both cases the algebraic multiplicty is 7, minimal and geometric multiplicities are both 3. Why does this mean knowing these multiplicies is not enough to deduce the Jordan normal form?
Office_Shredder Staff Emeritus Science Advisor Gold Member Messages 5,706 Reaction score 1,592 Nov 10, 2011 #2 Because those matrices have different Jordan normal forms even though all the multiplicities are the same
Because those matrices have different Jordan normal forms even though all the multiplicities are the same