How is the junction area of each diode calculated in this circuit?

AI Thread Summary
The discussion focuses on calculating the junction area of diodes in a circuit designed to maintain a specific output voltage and response to load current. The circuit requires Vo to be 3V with a load current (IL) of 0 A, and a change of 40mV per 1mA of load current, using a resistor value of 4.8K ohms. The saturation current for the four identical diodes is calculated as 2.339 x 10^(-16) A, while the saturation current for a standard diode with a 0.7V drop at 1mA is 6.19 x 10^(-16) A. The relative junction area is determined by dividing these two saturation currents, resulting in a value of 0.34. This calculation is essential for understanding the diode's performance in the given circuit configuration.
shaiqbashir
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Hi Guys!

My Question is this:

Dsign the circuit of the fig: so that Vo= 3V when IL = 0 A AND Vo changes by 40mV per 1mA of load current. the value of R = 4.8Kilo ohms. find the juction area of each diode (assume all four diodes are identical) relative to a diode with 0.7 V drop at 1mA current. Assume n=1.

The ans of this question is 0.34 but how it has been calculated.

Plz help
Thanks in advance:
 

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since we know that I(s) , i.e. the saturation current is proportonal to the junction area , calculate saturation current for the two cases as follows:
first for the four diodes ,given that they are identical, the voltage drop across each will be 3/4 = .75v, I = 2.5 mA. using eq I = I(s)exp(v/nVt) we get saturation curret for the given diode as 2.339 x 10^(-16).
Similarly for the given standard diode that is one with the voltage drop of .7v and I = 1mA
we get saturation current as 6.19 x 10^(-16).

since we have to find the relative area, simply dividing the above two saturation current would give the answer that is .34
 
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