Kepler's Law to Determine Period of Asteroid

AI Thread Summary
To determine the period of an asteroid orbiting at twice the Earth-Sun distance, Kepler's third law is applied, stating T² = Kr³. Given that the Earth-Sun distance is 1 AU, the asteroid's semi-major axis is 2 AU. By substituting R = 2 into the equation, R³ equals 8, leading to T² = 8K. Assuming K = 1 simplifies the calculation to T = √8, resulting in a period of approximately 2.83 years. Understanding this relationship between the asteroid's orbit and Earth's orbit is crucial for solving the problem.
scrambledeggs
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Homework Statement



A newly discovered asteroid orbits at twice the Earth-Sun distance. Find its period of orbit (in years).

Homework Equations



I know that I'm supposed to use Kepler's third law to determine this.
T2 = Kr3
K = 4∏2/GM

and the Earth-Sun distance is of course 1 Au

The Attempt at a Solution



I know that the answer should be √8 or about 2.83 years I just don't know how to get there. So frustrating because I know that this is a simple question.

Could it be that K = 1, and R=2 therefore R3 = 8?
 
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scrambledeggs said:

Homework Statement



A newly discovered asteroid orbits at twice the Earth-Sun distance. Find its period of orbit (in years).

Homework Equations



I know that I'm supposed to use Kepler's third law to determine this.
T2 = Kr3
K = 4∏2/GM

and the Earth-Sun distance is of course 1 Au

The Attempt at a Solution



I know that the answer should be √8 or about 2.83 years I just don't know how to get there. So frustrating because I know that this is a simple question.

Could it be that K = 1, and R=2 therefore R3 = 8?

Think about the relationship between this asteroid's orbit and the Earth's orbit.
 
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