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Ket help

  1. Dec 11, 2008 #1
    How do we show that the greatest accuracy in the |mn> state is |n| = m for the Mx and My components?
  2. jcsd
  3. Dec 11, 2008 #2


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    If M is an angular momentum operator, then Mx and My =0 for |n|=m.
  4. Dec 11, 2008 #3
    Yes M is an angular momentum operator. I also know that the components Mx and My do not commute. However, I do not understand how to show the greatest accuracy.

    Are you saying that Mx and My are orthogonal since they do not commute?
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