Kinematic Equation: Accel of Bullet Through 8.1cm Thick Board

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The discussion revolves around calculating the average acceleration of a bullet passing through an 8.1 cm thick board. The bullet enters at 452 m/s and exits at 298 m/s, prompting the use of kinematic equations to find acceleration. Participants emphasize the importance of identifying known variables, such as initial and final velocities, and the distance traveled through the board. Confusion arises regarding the time variable and the correct application of the kinematic equations, particularly in determining displacement. Ultimately, discrepancies in calculated acceleration values highlight the need for careful unit consistency and re-evaluation of the equations used.
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another one!

An indestructible bullet 1.86cm long is fired straight through a board that is 8.1cm thick. the bullet strikes the board with a speed of 452 m/s and emerges with a speed of 298 m/s. what is the average acceleration of the bullet through the board? answer in units of m/s^2

what would the length of the bullet and the width of the wall be used for in a kinematic equation? I know 452=v. and 298=v ... or is that wrong?
 
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Use the same formula for acceleration as your tennis ball question.
 
Think. You have to find the acceleration. List the things you know. Then look at your equations again. List all things that are relavant to kinematics.
 
what would the time variable be then?
 
If you don't know it label it as just t=?. But look at your equations, they all don't have something in it. Each one doesn't have one of these a,v,t,d so which oe should you use.
 
v=v.+a(t)

i know v=452m/s
v.=298 m/s
a= unknown
but i don't know what t should be, and it is known isn't it?
 
Do you need time?
Your missing a variable, distance.
There are other equations you can use.
 
oh, so I am using v^2=v.^2+2a(x-x.)? right?
 
Yes, List out everything you know before you even start a problem. This will help with some headaches. Look for what you don't know also and choose your equation with this information.
 
  • #10
so do I use 8.1 and 1.86 to find displacement?
 
  • #11
The bullet is only deaccelerated over 8.1cm. The width of the board.
 
  • #12
can you explain it in a different way. I don't understand how that fits into the equation.
 
  • #13
Your initial x=0 because the bullet has not been acted upon yet so your final x=8.1cm
 
  • #14
ok so the equation is 298^2=452^2+2a(8.1-0) right?
 
  • #15
looks good to me!
 
  • #16
the answer I am getting (-7129.63) is apparently incorrect. can you work it out and see if I am just doing my math wrong?
 
  • #17
whats the right answer?
 
  • #18
i don't know! i am doing the equation and I am getting that answer, but the computer is saying it is the wrong answer!
 
  • #19
well I'm getting a different answer than you also. Check your units. Stay consistent.
 
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