Hey guys, I'm confused on this problem: It is a typical sunny day. Assume your reaction time is 0.50 s and the acceleration of your car is –8.2 m/s2. What is the no-skid stopping distance when the car’s speed is initially 26.9 m/s? 1. The problem statement, all variables and given/known data a=-8.2 m/s^2 v0=26.9 m/s v=0 t=0.50s d=? 2. Relevant equations d=v0(t) +1/2a(t^2) v^2=v0^2+2ad 3. The attempt at a solution So I tried using the v^2=v0^2+2ad and got 44.12 m. However, the answer is 57.57. What did I do wrong? Thanks!