Kinematic Equations: Vector & Scalar Formulas

Click For Summary
The discussion focuses on the kinematic equations for motion with constant acceleration, emphasizing their vector and scalar forms. The three primary vector equations are presented, which can be expanded into scalar equations for each spatial component. A specific scalar equation, (v_f)^2 = (v_0)^2 + 2a(x_f - x_0), is discussed, with participants exploring its derivation from vector equations. The conversation also touches on the use of the vector dot product to combine these equations into a single expression. The thread concludes with a query about the missing variable in the derived equation.
fog37
Messages
1,566
Reaction score
108
Hello Forum,
the kinematic equations for motion with constant acceleration are vector equations which can each be expanded into 3 scalar (or component equations). The vector equations are:

v_f = v_0 + a (Delta_t)

r_f
= r_0 + v_0 (Delta_t) + (0.5) a (Delta_t)^2

r_f
= r_0 + (0.5) (v_f + v_0) (Delta_t)

From these three vector equation we can write the corresponding scalar equations for the x,y and z components.

What about the scalar equation (v_f)^2 = (v_0)^2 +2a (x_f -x_0) ? It can be written for each scalar component.
What is the corresponding vector equation for it from which it comes from?

thanks
fog37
 
Physics news on Phys.org
fog37 said:
It can be written for each scalar component.
That is, $$v_{xf}^2 = v_{x0}^2 + 2a_x (x_f - x_0) \\ v_{yf}^2 = v_{y0}^2 + 2a_y (y_f - y_0) \\ v_{zf}^2 = v_{z0}^2 + 2a_z (z_f - z_0)$$ Add the three equations together. Are you familiar with the vector dot product?
 
Thanks! I see how the addition of the three gives a single equation with dot products:

[ v_f dot v_f ] = [ v_0 dot v_0 ]+ 2 [a dot (r_f - r_0) ]

correct? Where does this equation come from? I guess it derives from that single differential equation dv/dt = a ...
 
I think you can get it by combining two of the equations in your first post. Note which variable is "missing" from this equation.
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

Similar threads

  • · Replies 49 ·
2
Replies
49
Views
4K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
6K
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 18 ·
Replies
18
Views
3K