Kinematic Problem Help: Calculating Distance and Speed of Two Moving Cars

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David drives at a constant speed of 31.0 m/s while Tina starts from rest and accelerates at 2.80 m/s² after he passes her. To determine how far Tina drives before passing David, two kinematic equations are needed: one for David's constant speed and another for Tina's acceleration. The variable 's' represents displacement, while 'u' denotes initial velocity. The discussion highlights the importance of calculating time to find the distance and speed at which Tina overtakes David. Understanding these equations and their variables is crucial for solving the problem effectively.
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Kinematic problem help!

Homework Statement



David is driving a steady 31.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 2.80 m/s^2 at the instant when David passes.

How far does Tina drive before passing David?

What is her speed as she passes him?



Homework Equations





The Attempt at a Solution



I know that there is two different cars moving seperatly and they will need two different equations, but I am not sure exactly how to go about this one?
 
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For the steady car s=vt, for the accelerating one s=ut+1/2at^2
 
OK I am just not sure what do with the equations, and what is s representing in these equations?
 
...and what is s representing in these equations?

's' is the standard abbreviation for displacement.

If you are finding it hard to use the equations directly it's probably because you don't quite know what you're heading for. This may help, or it my not, if both car's movement were mapped onto a distance-time graph would they cross? If so, what does this mean in respect to the equations.

~ Ek.
 
What does u represent in these equations and i am having trouble finding time, what steps do I need to find this?
 
There is a sticky describing the equations ( with better latex formatting).
Generally:
s = distance
t = time
a = acceleration
u = initial velocity
v = final velocity
 
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