Kinematics / Acceleration Problem

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Homework Help Overview

The problem involves kinematics, specifically focusing on an athlete's acceleration during a 100m sprint. The scenario describes linear acceleration for the first 60m, followed by constant speed for the remaining distance. Participants are tasked with calculating acceleration, drawing graphs, and determining total time taken.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of various kinematic equations to find acceleration and velocity, noting discrepancies in their calculations. Some express uncertainty about the correct formulas and seek clarification on their results.

Discussion Status

Some participants have offered numerical checks and alternative calculations, while others reflect on potential errors in their approaches. There is a mix of attempts to clarify concepts and resolve calculation issues, but no explicit consensus has been reached.

Contextual Notes

Participants are working under the constraints of the problem statement and are questioning their assumptions and calculations, particularly regarding the application of kinematic equations.

bakoo
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Homework Statement



Q1. In a 100m sprint the athlete can be assumed to accelerate linearly for the first 60m (which takes 7s to cover). For the remaining 40m the running speed is constant.
a) Determine the acceleration over the initial 60m. (5 marks)

b) Draw a graph of
i) acceleration v time (2 marks)
ii) speed v time (2 marks)
iii) distance v time (2 marks)

c) Determine the time taken to complete 100m both graphically and numerically. (4 marks)


Homework Equations



s = ut + 0.5at^2

s = displacement

t = time

a = acceleration

v = u + at

v = velocity

u = initial velocity

t = time

s = 0.5(u+v)t



The Attempt at a Solution



Acceleration = 2.163 m/s^3

Velocity = 15.141m/s


----

My problem is when i use other kinematic equations i don't get back to the same values as given in the problem.

when using formula

V^2 = U^2 +2as

i get a different velocty

and when i use formula

s = 0.5at^2

i get a different displacement.

---

So have i solved this corrent?

Any advice on what is the corrent formula or what is the correct answer would be most appreciated... thanks
 
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i think you may have made a numerical calculation error... check numbers again
 
Hey I'm not that good at physics or anything but i'll give it a go...

D=ut + .5 a t^2
60= 0 + 1/2 a 7^2
120 = 49a
a = 2.45 m/s...only slightly different to what you got.
 
Yes, i think you are 100% corrent, i am just going over all the Kinematic equations again.

I believe what i have done is a pre-school error.

I have done 0 * 7 and managed to get 7 =) which its supposed to be 0.

Think its all fixed, thanks...
 

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