Question reads: A bus travelling at 15.0m/s [E], started to slow down with an acceleration of 0.5m/s^2[W] as soon as it was abreast of a sports car. At the same instant, the sports car had a velocity of 6m/s [E] and was accelerating at 2.5m/s^2 [E]. At what time does the sports car catch up to the bus?
vf^2 = vi^2 + 2ad
d = Vit + 1/2at^2
The Attempt at a Solution
d = 15t + 1/2(-0.5)t^2 <-- bus
d = 6t + 1/2(2.5)t^2 <-- car
these are the two equations that i have and will i use these two equations to solve for time ? or distance?
im very confused at this point. ( putting two different object's speed together)
please help me further guide me with this problem.