Kinematics/free fall objects help.

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In kinematics, when analyzing a diver's motion, it's crucial to understand that gravity affects the object regardless of its direction. The diver springs upward with an initial speed of 1.8 m/s from a height of 3 meters, and the acceleration due to gravity is consistently -9.8 m/s². The highest point reached can be calculated using the initial and final velocities, confirming that gravity acts on the diver even as he ascends. The confusion often arises from associating gravity solely with downward motion, but it applies equally when an object is moving upward. Understanding this principle clarifies the calculations involved in free fall and projectile motion.
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In my honors course we are covering kinematics concepts. There was this problem which stumbled me but then I figured out what I did wrong. I just want to make sure my concept was right. Here is the problem...

A diver springs upward with an intial speed of 1.8 m/s from a board that is 3 meters above
the surface of the pool (his displacement is y = -3m). What is the highest point he reaches above the water.

So this was my equation

vi = 1.8 m/s
vf = 0 m/s
a = -9.8 m/s2
x = ?

Solved the equation and got x = 3.16 or 3.2

So the part that kind of confused me in the beginning was that I only had vi and vf. There had to be one more piece to solve the equation. Thats when I realized that gravity works even when the object has a positive velocity in the upward y direction. But then I started
doubting my self so I am kind of confused.
 
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So are you confused about when to use -9.8 as the acceleration?
 
Yeah basically. I was confused because he was going up and I kept thinking gravity in terms of falling down. So I wanted to make sure that gravity is the same when going up as well.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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