Kinematics HMWK Help: Gr 12 Physics Projectile Motion

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A Grade 12 physics student sought help with a projectile motion problem involving a rock thrown from a castle wall. The initial velocity was 12 m/s at a 42-degree angle, and the rock landed 9.5 m below the launch point. After determining the vertical and horizontal components of velocity, the student calculated the time of flight as 2.4 seconds and the width of the moat as 22 meters. The discussion also covered how to find the velocity at impact, which the student successfully solved using the appropriate kinematic equation. The collaborative nature of the forum helped the student progress through the problem effectively.
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Kinematics HMWK help!

hi, I am in gr 12 physics and i need help in a kinematics question about Projectile motion... here is the question:

"a medievil prince is trapped in a castle wraps a message around a rock and throws it from the top of the castlewall with an initial velocity of 12 m/s [42 degrees above the horizontal]. The rock lands just on the far side of the casltes moat, at a level of 9.5 m below the initial level. Determine the (a) time of flight (b) width of moat and (c) velocity at impact"

i really can't figure this out and i need help ASAP:eek:
 
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Hey, welcome aboard!
What work have you done on this problem?
What do you know? What are you looking for? Any ideas of what equation(s) you'll need to use?
 
ok well what i have so far is my vertical and horizontal velocities, which are 8.0 m/s and 8.9 m/s respectively...and i don't know where to go from here... i tried using d=v1t + 1/2 at*2 but when i put it in the quadratic formula i can't get it to work :confused: so i don't know where to go from here
 
humaders99 said:
ok well what i have so far is my vertical and horizontal velocities, which are 8.0 m/s and 8.9 m/s respectively...and i don't know where to go from here... i tried using d=v1t + 1/2 at*2 but when i put it in the quadratic formula i can't get it to work :confused: so i don't know where to go from here

OK, so it sounds like you're solving for x and y components separately, which is very good.

You know more than that: assign a value for the initial x position (I'd use 0m) and y position (which you could set at zero, but since the rock falls below the throw line, you'd have a lot of negatives flying around. I don't like negatives, so I'd set the initial y position as the height of the wall--which is given). You also know that there is no acceleration in the x direction, and the acceleration in the y direction is acceleration due to gravity.
I suggest starting by solving for time, using an equation involving y-components only.
 
ok ... now i have figured out the time ... it is 2.4 s ... how would i figure out the length of the moat? would i have to use the x components now? and if i do how would i do that?
 
yes, yes!

I'd use x=x_{0}+v_{0x}t+\frac{1}{2}at^2

Remember that x acceleration = 0.
 
ok i got the length of the moat (22 m) ! thanks for ur help... but i have one more question that i hope u can answer... how would i figure out the velocity at impact?
 
nvm... i got it ... i just used V_2^2=V_1^2+2ad... and i got the answer :) thnx again for ur help
 
hey I am new here and need some help with a few basic questions
 
  • #10
is anyone online?
 
  • #11
can anyone in here help me with some questions
 
  • #12
it might help if you posted your question...
 
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